On the weekends, Paul jogs $ \dfrac{9}{{10}} $ mile. On the weekdays, Paul jogs $ \dfrac{5}{{10}} $ mile. How many more miles does Paul jog on the weekends than on a weekday?
Answer
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Hint: We can clearly see that Paul walks more on weekends than he walks on weekdays. Therefore, to answer this question, we need to find the difference between both these distances. For this we need to subtract the distance covered by him on the weekdays from the distance covered by him on weekends while jogging. We will use the concept of subtraction of fraction to get our final answer.
Complete step-by-step answer:
The distance covered by Paul on weekends $ = \dfrac{9}{{10}}mile $ .
The distance covered by Paul on weekdays $ = \dfrac{5}{{10}}mile $ .
To find out the difference between both these distances, we will now subtract $ \dfrac{5}{{10}}mile $ from $ \dfrac{9}{{10}}mile $ .
$ \dfrac{9}{{10}} - \dfrac{5}{{10}} $
Here, we can see that the denominator of both the fraction is the same. Therefore, we need not to use the LCM method for that. We only have to make the denominator common and subtract numerators only.
$ \Rightarrow \dfrac{9}{{10}} - \dfrac{5}{{10}} = \dfrac{{9 - 5}}{{10}} = \dfrac{4}{{10}} $
We can also convert this fraction into the simplest form.
$ \dfrac{4}{{10}} = \dfrac{{2 \times 2}}{{2 \times 5}} = \dfrac{2}{5} $
Hence, we can say that Paul jogs $ \dfrac{4}{{10}}mile $ or $ \dfrac{2}{5}mile $ on weekends than he jogs on weekdays.
So, the correct answer is “ $ \dfrac{2}{5} $ mile”.
Note: In this type of question, where the subtraction of fraction is required, we just need to follow three simple steps. First, we need to make sure that the denominators are the same. Second, we need to subtract the numerators and put that answer over the same denominator. Finally, we can simplify the fraction to its reduced form if needed.
Complete step-by-step answer:
The distance covered by Paul on weekends $ = \dfrac{9}{{10}}mile $ .
The distance covered by Paul on weekdays $ = \dfrac{5}{{10}}mile $ .
To find out the difference between both these distances, we will now subtract $ \dfrac{5}{{10}}mile $ from $ \dfrac{9}{{10}}mile $ .
$ \dfrac{9}{{10}} - \dfrac{5}{{10}} $
Here, we can see that the denominator of both the fraction is the same. Therefore, we need not to use the LCM method for that. We only have to make the denominator common and subtract numerators only.
$ \Rightarrow \dfrac{9}{{10}} - \dfrac{5}{{10}} = \dfrac{{9 - 5}}{{10}} = \dfrac{4}{{10}} $
We can also convert this fraction into the simplest form.
$ \dfrac{4}{{10}} = \dfrac{{2 \times 2}}{{2 \times 5}} = \dfrac{2}{5} $
Hence, we can say that Paul jogs $ \dfrac{4}{{10}}mile $ or $ \dfrac{2}{5}mile $ on weekends than he jogs on weekdays.
So, the correct answer is “ $ \dfrac{2}{5} $ mile”.
Note: In this type of question, where the subtraction of fraction is required, we just need to follow three simple steps. First, we need to make sure that the denominators are the same. Second, we need to subtract the numerators and put that answer over the same denominator. Finally, we can simplify the fraction to its reduced form if needed.
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