What is the number of atoms in an end centered unit cell?
a.) 2
b.) 4
c.) 1
d.) 6
Answer
614.4k+ views
Hint: End centered unit cell is present in the crystal lattice. We can analyse the number of atoms by the position of constituent particles. In the end centered, look into the 8 corners and 2 opposite faces of a cube.
Complete step by step answer:
Firstly, let us know about the unit cell. We know crystal lattice is made up of numerous unit cells.
Now, the number of atoms, ions, or molecules in a unit cell can be easily known by the nature and position of constituent particles.
We can see that there are various types of unit cell i.e. primitive cubic, body-centred cubic, face-centred cubic, and end-centred cubic unit cell.
Talking about the end-centred cubic unit cell, 8 atoms are placed on the 8 corners of the cube and 1 atom each is placed on two opposite faces of the cube.
Thus, we can say that, if 8 atoms are present on 8 corners, then each atom will contribute $\dfrac{1}{8}$$^{th}$ portion.
So, 8$\times$$\dfrac{1}{8}$=1 atom
Now, if 2 atoms located at the opposite faces, each contributes $\dfrac{1}{2}$$^{th}$ portion
So, 2$\times$$\dfrac{1}{2}$=1 atom.
Therefore, the total number of atoms is 2. The correct option is A.
Note: Don’t get confused between the types of unit cells. In the end-centred unit cell just relate the term to the corners and opposite faces of the cube, or we can say the atoms present at the centre in the cell.
Complete step by step answer:
Firstly, let us know about the unit cell. We know crystal lattice is made up of numerous unit cells.
Now, the number of atoms, ions, or molecules in a unit cell can be easily known by the nature and position of constituent particles.
We can see that there are various types of unit cell i.e. primitive cubic, body-centred cubic, face-centred cubic, and end-centred cubic unit cell.
Talking about the end-centred cubic unit cell, 8 atoms are placed on the 8 corners of the cube and 1 atom each is placed on two opposite faces of the cube.
Thus, we can say that, if 8 atoms are present on 8 corners, then each atom will contribute $\dfrac{1}{8}$$^{th}$ portion.
So, 8$\times$$\dfrac{1}{8}$=1 atom
Now, if 2 atoms located at the opposite faces, each contributes $\dfrac{1}{2}$$^{th}$ portion
So, 2$\times$$\dfrac{1}{2}$=1 atom.
Therefore, the total number of atoms is 2. The correct option is A.
Note: Don’t get confused between the types of unit cells. In the end-centred unit cell just relate the term to the corners and opposite faces of the cube, or we can say the atoms present at the centre in the cell.
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