Question

Nitric oxide reacts with bromine and gives nitrosyl-bromide as per reaction given
below:
\[2N{{O}_{\left( g \right)}}+B{{r}_{2\left( g \right)}}\rightleftharpoons 2NOB{{r}_{\left( g \right)}}\]
When 0.087 mole of \[NO\] and 0.0437 mole of \[B{{r}_{2}}\]are mixed is a closed container at
constant temperature, 0.0518 mole of \[NOBr\] is obtained at equilibrium. Calculate
equilibrium amount of nitric oxide and bromine.

Answer 1

Hint: In a chemical reaction, chemical equilibrium is the state where the two reactants and objects are available in fixations which have no more ability to change with time so that there is none of the recognizable change in the properties of the system.

Complete step by step solution:
0.0518 moles of \[NO\] form 0.0518 moles of \[NOBr\].

Equilibrium amount of \[NO\]is \[0.087-0.0518=0.0352~mol\]

\[\dfrac{0.0518}{2}\] moles of bromine forms moles of \[NOBr\].

The equilibrium amount of bromine is \[0.0437-\dfrac{0.0518}{2}=0.0178~mol\].

The equilibrium constant expression is
\[{{K}_{c}}=\dfrac{{{[NOBr]}^{2}}}{{{[NO]}^{2}}[B{{r}_{2}}]}=\dfrac{{{(0.0518)}^{2}}}{{{(0.0352)}^{2}}(0.0178)}=121.66\].
This state results when forward reaction continues at a similar rate as the backward reaction. The reactions give direction to the forward reaction and in the backward reaction are generally not zero order0; however, they can be equivalent.

Accordingly, there are none of the net changes in the centralizations of the reactants and products. Such a state is known as a unique equilibrium.

In the static part, when we state that a body is in equilibrium, what we mean is that the body isn't moving at all despite the fact that there might be forces following up on it. (As a rule, equilibrium implies that there is no acceleration i.e., the body is moving with steady velocity yet in this extraordinary case we take this consistent to be zero).

Note: The ratio of the concentrations of the reactants and products is known as the equilibrium constant articulation. At the point when the response arrives at equilibrium, the connection between the concentrations of the reactants and products portrayed by the equilibrium constant articulation will consistently be the equivalent.