
Mukesh borrowed Rs. 75,000 from a bank. If the rate of interest is 15% per annum, find the amount he would be paying after $1\dfrac{1}{2}$ years if the interest is compounded annually.
Answer
624.9k+ views
Hint: Use compound interest formula for the calculation of amount ‘$A$’, given by: \[A=P{{\left( 1+\dfrac{r}{n} \right)}^{nt}}\]. Here, ‘$P$’ is the principal amount, ‘$r$’ is the rate per annum, ‘$t$’ is the time in years and ‘$n$’ is the number of times the interest is given in one year.
Complete step-by-step solution -
Compound interest is the addition of interest to the principal sum of a loan or deposit. It is the result of reinvesting interest, rather than paying it out, so the interest in the next period is then earned on the principal sum plus previously accumulated interest.
The total accumulated amount $A$ , on the principal sum \[P\] plus compound interest $I$ is given by the formula \[A=P{{\left( 1+\dfrac{r}{n} \right)}^{nt}}\].
Here, \[A\] is the amount obtained, $t$ is the number of years, \[r\] is the rate, $P$ is the principal and \[n\] is the number of times the interest is given in a year.
We have been given, \[P=75000,\text{ }r=15%,\text{ }t=1\dfrac{1}{2}=\dfrac{3}{2}years\text{ and }n=1\].
Now, substituting the value of $P,r,t\text{ and }n$ in the formula to find amount, we get,
$\begin{align}
& A=75000{{\left( 1+\dfrac{15}{100\times 1} \right)}^{1\times \dfrac{3}{2}}} \\
& =75000{{\left( 1+\dfrac{15}{100} \right)}^{\dfrac{3}{2}}} \\
\end{align}$
Taking L.C.M we get,
\[\begin{align}
& A=75000{{\left( \dfrac{100+15}{100} \right)}^{\dfrac{3}{2}}} \\
& =75000{{\left( \dfrac{115}{100} \right)}^{\dfrac{3}{2}}} \\
& =75000\times \dfrac{{{\left( 115 \right)}^{\dfrac{3}{2}}}}{{{\left( 100 \right)}^{\dfrac{3}{2}}}} \\
& =75000\times \dfrac{{{\left( 115 \right)}^{\dfrac{3}{2}}}}{1000} \\
& =75\times {{\left( 115 \right)}^{\dfrac{3}{2}}} \\
\end{align}\]
This can be written as,
$A=75\times 115\times \sqrt{115}$
Substituting, $\sqrt{115}=10.72$ we get,
$\begin{align}
& A=75\times 115\times 10.72 \\
& \text{ =92460} \\
\end{align}$
Hence, the amount Mukesh has to pay after $1\dfrac{1}{2}$ years is Rs. 92,460.
Note: Here, the value of $n$ must be substituted carefully. We have to read the question carefully as it is given that the rate is compounded annually, therefore, $n=1$ is substituted. We must divide the given rate by 100 and then substitute in the equation.
Complete step-by-step solution -
Compound interest is the addition of interest to the principal sum of a loan or deposit. It is the result of reinvesting interest, rather than paying it out, so the interest in the next period is then earned on the principal sum plus previously accumulated interest.
The total accumulated amount $A$ , on the principal sum \[P\] plus compound interest $I$ is given by the formula \[A=P{{\left( 1+\dfrac{r}{n} \right)}^{nt}}\].
Here, \[A\] is the amount obtained, $t$ is the number of years, \[r\] is the rate, $P$ is the principal and \[n\] is the number of times the interest is given in a year.
We have been given, \[P=75000,\text{ }r=15%,\text{ }t=1\dfrac{1}{2}=\dfrac{3}{2}years\text{ and }n=1\].
Now, substituting the value of $P,r,t\text{ and }n$ in the formula to find amount, we get,
$\begin{align}
& A=75000{{\left( 1+\dfrac{15}{100\times 1} \right)}^{1\times \dfrac{3}{2}}} \\
& =75000{{\left( 1+\dfrac{15}{100} \right)}^{\dfrac{3}{2}}} \\
\end{align}$
Taking L.C.M we get,
\[\begin{align}
& A=75000{{\left( \dfrac{100+15}{100} \right)}^{\dfrac{3}{2}}} \\
& =75000{{\left( \dfrac{115}{100} \right)}^{\dfrac{3}{2}}} \\
& =75000\times \dfrac{{{\left( 115 \right)}^{\dfrac{3}{2}}}}{{{\left( 100 \right)}^{\dfrac{3}{2}}}} \\
& =75000\times \dfrac{{{\left( 115 \right)}^{\dfrac{3}{2}}}}{1000} \\
& =75\times {{\left( 115 \right)}^{\dfrac{3}{2}}} \\
\end{align}\]
This can be written as,
$A=75\times 115\times \sqrt{115}$
Substituting, $\sqrt{115}=10.72$ we get,
$\begin{align}
& A=75\times 115\times 10.72 \\
& \text{ =92460} \\
\end{align}$
Hence, the amount Mukesh has to pay after $1\dfrac{1}{2}$ years is Rs. 92,460.
Note: Here, the value of $n$ must be substituted carefully. We have to read the question carefully as it is given that the rate is compounded annually, therefore, $n=1$ is substituted. We must divide the given rate by 100 and then substitute in the equation.
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