
Mr. Rai bought a machine that was tested at Rs 320. He was given successive discounts of 20% and 10%, then the price he paid was
A.Rs 120.40
B.Rs 220.40
C.Rs 230.40
D.None of these
Answer
492.6k+ views
Hint: Here in the given question we are asked to find the price of a machine after the successive discount given. Successive discounts mean getting a discount on a product more than once. Here the first discount will be subtracted from the marked price to get the selling price, further this selling price will be considered as the marked price for the second discount and will be subtracted to get the net price.
Complete step-by-step answer:
The marked price of the machine is Rs 320, on implementing the first discount of 20% on marked price we get
\[ \Rightarrow 320 - \dfrac{{20}}{{100}} \times 320\] --------(1)
On simplifying equation (1)
\[ \Rightarrow 320 - 2 \times 32\]
\[
\Rightarrow 320 - 64 \\
\Rightarrow Rs\,256 \;
\]
Now after applying the first discount of 20% we get the new price to be Rs 256 which will be considered as marked price for the further process. Implementing the second discount of 10% on Rs 256 we get
\[ \Rightarrow 256 - \dfrac{{10}}{{100}} \times 256\] -------(2)
On simplifying equation (2) we get
\[
\Rightarrow 256 - \dfrac{1}{{10}} \times 256 \\
\Rightarrow 256 - \dfrac{{256}}{{10}} \\
\Rightarrow 256 - 25.6 \\
\Rightarrow Rs\,220.40 \;
\]
Therefore, the selling price of the machine after the successive discount will be Rs 220.40
So, the correct answer is “Rs. 220.40”.
Note: Discount means to deduct the price of the item. Remember discount is always calculated on the marked price. To find the successive discount when there are two discounts given as a% and b% we can use the following formula \[\left( {a + b - \dfrac{{a \times b}}{{100}}} \right)\% \]. Similarly, when three discounts are given as a%, b% and c% we first find the discount of a% and b% then use this discount and c% to find the total discount. Always the total discount should be subtracted from the marked price.
Complete step-by-step answer:
The marked price of the machine is Rs 320, on implementing the first discount of 20% on marked price we get
\[ \Rightarrow 320 - \dfrac{{20}}{{100}} \times 320\] --------(1)
On simplifying equation (1)
\[ \Rightarrow 320 - 2 \times 32\]
\[
\Rightarrow 320 - 64 \\
\Rightarrow Rs\,256 \;
\]
Now after applying the first discount of 20% we get the new price to be Rs 256 which will be considered as marked price for the further process. Implementing the second discount of 10% on Rs 256 we get
\[ \Rightarrow 256 - \dfrac{{10}}{{100}} \times 256\] -------(2)
On simplifying equation (2) we get
\[
\Rightarrow 256 - \dfrac{1}{{10}} \times 256 \\
\Rightarrow 256 - \dfrac{{256}}{{10}} \\
\Rightarrow 256 - 25.6 \\
\Rightarrow Rs\,220.40 \;
\]
Therefore, the selling price of the machine after the successive discount will be Rs 220.40
So, the correct answer is “Rs. 220.40”.
Note: Discount means to deduct the price of the item. Remember discount is always calculated on the marked price. To find the successive discount when there are two discounts given as a% and b% we can use the following formula \[\left( {a + b - \dfrac{{a \times b}}{{100}}} \right)\% \]. Similarly, when three discounts are given as a%, b% and c% we first find the discount of a% and b% then use this discount and c% to find the total discount. Always the total discount should be subtracted from the marked price.
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