Question

What is the molar mass of adrenaline \[({C_9}{H_{13}}N{O_3})\] ?

Answer 1

Hint :Molar mass: It is the summation of atomic masses of each element present in the compound. Before summation, the atomic mass of each element must be multiplied by the number of atoms present in the compound.

Complete Step By Step Answer:
To calculate the molar mass of given compound, we need to follow certain steps which are as follows:
Step-1: Finding the number of atoms of each element present in the compound.
In adrenaline i.e., \[{C_9}{H_{13}}N{O_3}\], the number of atoms of substituents are as follows-
Number of Carbon atoms \[ = 9\]
Number of Hydrogen atoms \[ = 13\]
Number of Nitrogen atoms \[ = 1\]
Number of Oxygen atoms \[ = 3\]
Step-2: Finding the atomic mass of each element present in the compound.
In adrenaline i.e., \[{C_9}{H_{13}}N{O_3}\], the atomic mass of substituents are as follows-
Atomic mass of Carbon atoms \[ = 12gmo{l^{ - 1}}\]
Atomic mass of Hydrogen atoms \[ = 1gmo{l^{ - 1}}\]
Atomic mass of Nitrogen atoms \[ = 14gmo{l^{ - 1}}\]
Atomic mass of Oxygen atoms \[ = 16gmo{l^{ - 1}}\]
Step-3: Calculating the molar mass of the given compound.
Molar mass is equal to the summation of the product of the number of atoms and atomic mass of each element present in the compound.
Therefore, atomic mass of adrenaline i.e., \[{C_9}{H_{13}}N{O_3}\] can be written as follows:
\[\begin{array}{l}m = 9 \times 12 + 13 \times 1 + 1 \times 14 + 3 \times 16\\\,\,\,\, \Rightarrow 183gmo{l^{ - 1}}\end{array}\]
Hence the molar mass of adrenaline is \[183gmo{l^{ - 1}}\].

Note :
Molar mass is always calculated for one mole of the compound. If in case, n moles of compound is given then we need to divide the mass calculated by the number of moles present i.e., n. Also, molecular structures do not affect the molar mass of the compound as it completely depends on the number of atoms of substituents and their atomic masses.