Question

Mark the odd one out (w.r.t ploidy level)
A. nucellus
B. integument
C. funicle
D. embryo sac.

Answer 1

Hint: The term "ploidy" expresses the quantity of sets of chromosomes in a biological cell and marked by an "X". A diploid genotype incorporates paired (homologous) units of chromosomes in the nucleus of every cell, one from each parent. "Polyploidy" is the multiplication of full units of chromosomes.

Complete answer:
To solve this question, at first, we have to know the ploidy level of cells. Ploidy level is defined as the number of chromosome sets in somatic cells of the diplophase (2n) or gametophytic cells of the haplophase (1n). It is indicated by way of means of number followed by the x letter. Diploid cells have sets of chromosomes and are indicated by way of means of 2x.
Now let us find the solution from the given option-
Considering if the ploidy of the plant is 2n, nucellus (located in the integumentary) has abundant reserve foods materials. Its ploidy is 2n.
Integument is the network of capabilities that forms the covering of an organism. The integument delimits the organism body, isolating it from the surroundings and protecting it from foreign matter. It has a ploidy 2n.
Funicle is the stalk that attaches an ovule to the placenta in the ovary of a flowering plant. It includes a strand of undertaking tissue main from the placenta into the chalaza. Funicle has ploidy 2n.
Female gametophytes additionally referred to as an embryo sac (produced via means of meiotic department from Megaspore mom cell) has ploidy n.

Thus, the right answer is option D. i.e. embryo sac.

Note: Different levels of endosperm ploidy depend upon the sort of embryo sac, consequently endosperm ploidy levels can range from 2n (Oenothera-kind of embryo sac) to nine n (Peperomia-kind of embryo sac).