Marine fish when placed in tap water bursts because of (a) Endosmosis (b) Exosmosis (c) Diffusion (d) Plasmolysis
Hint: Bursting of cells happens because the marine fish are accustomed to salt water which has a higher solute concentration when compared with freshwater.
Complete Answer: Endosmosis is the movement of water inside of a cell when the cell is placed in a hypotonic solution. Endosmosis occurs because the concentration of the solute of the solution surrounding the cell is less than the concentration of solute inside the cytoplasm of the cell. Exosmosis is the movement of water outside the cell when the cell is placed in a hypertonic solution. Exosmosis occurs because the concentration of the solute of the solution surrounding the cell is more than the concentration of solute inside the cytoplasm of the cell. Plasmolysis is the process by which a cell loses water when placed in a hypertonic solution. The cell when placed in a hypertonic solution loses water and becomes flaccid. This results in a loss of turgor pressure and causes the protoplasm of the cell to separate from the cell wall. Diffusion is the movement of water molecules from a gradient of higher concentration to a gradient of lower concentration. The cells of marine fish burst when introduced to tap water. The introduction of the marine fish to freshwater would result in the rushing of water into the cells because of the process of endocytosis and cause the cells of the marine fish to swell and burst.
Therefore, the correct option is (a) Endosmosis
Note: Gaps are created between the cell wall and protoplasm during plasmolysis which results in the shrinking of the cell. The cell becomes flaccid after the movement of water outside the cytoplasm of the cell during exosmosis. The movement of water inside the cell causes the cell to swell during endosmosis.