
Major product of chlorination of ethyl benzene is:
A. m-chloroethyl benzene
B. p- chloroethyl benzene
C. chlorobenzene
D. o-chloroethyl benzene
Answer
510.3k+ views
Hint: Alkyl halide also known by the name haloalkanes or halogenoalkanes which are generally those chemical compounds which are often derived from alkanes which contain one or more halogens. These are formed by the replacement of hydrogen atoms in an aliphatic hydrocarbon by any halogen atom.
Complete answer:
Ethyl benzene is an example of aromatic compounds where aromatic compounds are those compounds which have benzene ring in them i.e. an alkyl group is attached with benzene here the alkyl group is ethyl which have 2 carbon atoms in them and ethyl benzene is represented by the chemical formula ${{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}$ ${{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}$.
Chlorination is the process of adding chlorine in the given compound, product formed after chlorination is alkyl halide or aryl halide where alkyl halide is adding chlorine to alkyl group whereas if the compound given is of aryl nature then after chlorination it converts into aryl halide where halide is halogen here chlorine is act as halogen.
Chlorination of ethyl benzene is produces generally two products known as 1-chloro-1-phenylethane which is secondary alkyl halide or known as o-chloroethyl benzene and 2-chloro-1-phenylethane i.e. m-chloroethyl benzene out of these two 1-chloro-1-phenylethane is major product.
Hence option D is the correct answer.
Note:
o-chloroethyl benzene, m-chloroethyl benzene and p-chloroethyl benzene here these are known by the terms ortho, meta and para respectively. These terms generally depend upon the position of attachment of the alkyl group.
Complete answer:
Ethyl benzene is an example of aromatic compounds where aromatic compounds are those compounds which have benzene ring in them i.e. an alkyl group is attached with benzene here the alkyl group is ethyl which have 2 carbon atoms in them and ethyl benzene is represented by the chemical formula ${{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}$ ${{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{3}}$.
Chlorination is the process of adding chlorine in the given compound, product formed after chlorination is alkyl halide or aryl halide where alkyl halide is adding chlorine to alkyl group whereas if the compound given is of aryl nature then after chlorination it converts into aryl halide where halide is halogen here chlorine is act as halogen.
Chlorination of ethyl benzene is produces generally two products known as 1-chloro-1-phenylethane which is secondary alkyl halide or known as o-chloroethyl benzene and 2-chloro-1-phenylethane i.e. m-chloroethyl benzene out of these two 1-chloro-1-phenylethane is major product.
Hence option D is the correct answer.
Note:
o-chloroethyl benzene, m-chloroethyl benzene and p-chloroethyl benzene here these are known by the terms ortho, meta and para respectively. These terms generally depend upon the position of attachment of the alkyl group.
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