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Let X denote the sum of the numbers obtained when two fair dice are rolled. Find the variance and the standard deviation of X.

Answer
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Hint: Find the probability distribution for X and then find the mean of the distribution. Using the mean, you can calculate the variance and standard deviation of X.

Complete step-by-step answer:
It is given that X denotes the sum of the numbers obtained when two fair dice are rolled.
X can take values from 2(1 + 1) through 12 (6 + 6). Hence, X can take values 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12.
We know that the total outcome when two dice are rolled is 6 × 6, that is 36.
Let us find the probability distribution of X.

XPossible OutcomesP(X)
2(1, 1)136
3(2, 1) (1, 2)236
4(3, 1) (2, 2) (1, 3)336
5(4, 1) (3, 2) (2, 3) (1, 4)436
6(5, 1) (4, 2) (3, 3) (2, 4) (1, 5)536
7(6, 1) (5, 2) (4, 3) (3, 4) (2, 5) (1, 6)636
8(6, 2) (5, 3) (4, 4) (3, 5) (2, 6)536
9(6, 3) (5, 4) (4, 5) (3, 6)436
10(6, 4) (5, 5) (4, 6)336
11(6, 5) (5, 4)236
12(6, 6) 136


Now, we find the mean of the distribution.
Mean, X¯=XP(X)
X¯=136[2×1+3×2+4×3+5×4+6×5+7×6+8×5+9×4+10×3+11×2+12×1]
X¯=25236
X¯=7
We now find the variance of the distribution as follows:
Variance, σ2=X2P(X)X¯2
σ2=136[22×1+32×2+42×3+52×4+62×5+72×6+82×5+92×4+102×3+112×2+122×1]72
σ2=19743649
σ2=1974176436
σ2=21036
σ2=356
We can calculate the standard deviation by taking the square root of the variance.
σ=356
Hence, the value of variation is 356 and the value of standard deviation is 356.

Note: Mean can also be found by multiplying X with the number of possible outcomes and adding them and dividing by the total number of outcomes in that case, it is not necessary to find the probability of each outcome.