
Let F(x) = f(x)g(x)h(x) for all real x, where f(x), g(x) and h(x) are differentiable functions. At some point ${{\text{x}}_0}$, ${\text{F' (}}{{\text{x}}_0}){\text{ = 21 F(}}{{\text{x}}_0})$, ${\text{f' (}}{{\text{x}}_0}){\text{ = 4 f(}}{{\text{x}}_0})$, ${\text{g' (}}{{\text{x}}_0}){\text{ = - 7 g(}}{{\text{x}}_0})$ and ${\text{h' (}}{{\text{x}}_0}){\text{ = k h(}}{{\text{x}}_0})$. Then k is equal to
Answer
603.3k+ views
Hint: In this question we will apply the product rule of differentiation and also use the given conditions to find the value of k to solve the given question. We will apply the differentiation on the condition F(x) = f(x)g(x)h(x) and use the other given conditions accordingly.
Complete step-by-step answer:
Now, we are given F(x) = f(x)g(x)h(x). Also, there are conditions given in the question. ${\text{F' (}}{{\text{x}}_0}){\text{ = 21 F(}}{{\text{x}}_0})$, ${\text{f' (}}{{\text{x}}_0}){\text{ = 4 f(}}{{\text{x}}_0})$, ${\text{g' (}}{{\text{x}}_0}){\text{ = - 7 g(}}{{\text{x}}_0})$, ${\text{h' (}}{{\text{x}}_0}){\text{ = k h(}}{{\text{x}}_0})$.
Now by seeing the condition we know that we have to use differentiation. We will use the product rule of differentiation in F(x) = f(x)g(x)h(x). Now, product rule states that if a function h(x) is the product of function f(x) and g(x) and derivative of h(x) is written as,
h(x) = f(x) g(x)
$\dfrac{{{\text{d h(x)}}}}{{{\text{dx}}}}{\text{ = g(x)}}\dfrac{{{\text{d f(x)}}}}{{{\text{dx}}}}{\text{ + f(x)}}\dfrac{{{\text{d g(x)}}}}{{{\text{dx}}}}$
Now, differentiating F(x) = f(x)g(x)h(x) both sides with respect to x and applying product rule, we get
${\text{F' (x) = f'(x)g(x)h(x) + f(x)g'(x)h(x) + f(x)g(x)h'(x)}}$
Now, using conditions given in the questions in the above equation, we get
21 F(x) = 4f(x)g(x)h(x) – 7f(x)g(x)h(x) + kf(x)g(x)h(x)
Putting value of F(x) in the above equation,
$\Rightarrow$ 21(f(x)g(x)h(x)) = 4f(x)g(x)h(x) – 7f(x)g(x)h(x) + kf(x)g(x)h(x)
Taking f(x)g(x)h(x) common from both sides,
$\Rightarrow$ 21(f(x)g(x)h(x)) = f(x)g(x)h(x) (4 – 7 + k)
$\Rightarrow$ 21 = 4 – 7 + k
$\Rightarrow$ k = 24
So, the value of k is 24.
Note: To solve such types of questions we will follow a few steps to find the solution of the given problem. First, we will select the condition with which we will start. Then, we will apply the differentiation on that property. After it, we will use the given conditions in the question to solve the question correctly.
Complete step-by-step answer:
Now, we are given F(x) = f(x)g(x)h(x). Also, there are conditions given in the question. ${\text{F' (}}{{\text{x}}_0}){\text{ = 21 F(}}{{\text{x}}_0})$, ${\text{f' (}}{{\text{x}}_0}){\text{ = 4 f(}}{{\text{x}}_0})$, ${\text{g' (}}{{\text{x}}_0}){\text{ = - 7 g(}}{{\text{x}}_0})$, ${\text{h' (}}{{\text{x}}_0}){\text{ = k h(}}{{\text{x}}_0})$.
Now by seeing the condition we know that we have to use differentiation. We will use the product rule of differentiation in F(x) = f(x)g(x)h(x). Now, product rule states that if a function h(x) is the product of function f(x) and g(x) and derivative of h(x) is written as,
h(x) = f(x) g(x)
$\dfrac{{{\text{d h(x)}}}}{{{\text{dx}}}}{\text{ = g(x)}}\dfrac{{{\text{d f(x)}}}}{{{\text{dx}}}}{\text{ + f(x)}}\dfrac{{{\text{d g(x)}}}}{{{\text{dx}}}}$
Now, differentiating F(x) = f(x)g(x)h(x) both sides with respect to x and applying product rule, we get
${\text{F' (x) = f'(x)g(x)h(x) + f(x)g'(x)h(x) + f(x)g(x)h'(x)}}$
Now, using conditions given in the questions in the above equation, we get
21 F(x) = 4f(x)g(x)h(x) – 7f(x)g(x)h(x) + kf(x)g(x)h(x)
Putting value of F(x) in the above equation,
$\Rightarrow$ 21(f(x)g(x)h(x)) = 4f(x)g(x)h(x) – 7f(x)g(x)h(x) + kf(x)g(x)h(x)
Taking f(x)g(x)h(x) common from both sides,
$\Rightarrow$ 21(f(x)g(x)h(x)) = f(x)g(x)h(x) (4 – 7 + k)
$\Rightarrow$ 21 = 4 – 7 + k
$\Rightarrow$ k = 24
So, the value of k is 24.
Note: To solve such types of questions we will follow a few steps to find the solution of the given problem. First, we will select the condition with which we will start. Then, we will apply the differentiation on that property. After it, we will use the given conditions in the question to solve the question correctly.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

