Question

In glycolysis, enzyme enolase produces
(A) Phosphoglyceric acid
(B) Phosphoenol pyruvate
(C) Phosphoglyceraldehyde
(D) Pyruvate

Answer 1

Hint: Glycolysis is the first process that takes place in the respiration. It is also called the EMP pathway. The full form of EMP pathway is Gustav Emden, Otto Meyerhof and J. Parnas pathway since they gave the scheme for glycolysis. It is a common pathway that occurs in both aerobic and anaerobic respiration.

Complete answer:
Glycolysis takes place aerobically or anaerobically but it doesn’t involve molecular oxygen. In this process the complex molecules like glucose, fructose etc. break down into the simpler compounds like pyruvate, pyruvic acid and hydrogens with the certain amount of energy released. Hence it is known as glycolysis. It involves a series of ten steps. Glycolysis or $EMP$ pathway takes place in two phases. They are preparatory phase and pay off phase. The preparatory phase deals with the first five of ten catalytic reactions. And the payoff phase deals with the last five reactions.

In the ninth step, reversible dehydration takes place. In this, $2 - phosphoglycerate$ is converted into phosphoenolpyruvate. With the release of water molecules. The enzyme enolase is used to catalyze this reaction. Hence, the enzyme enolase produces phosphoenol pyruvate.

Hence, the correct answer is Option (B)

Note: The energy released forms the glycolysis process is in the form of ATP and NADH. The pyruvate that is produced as the result of glycolysis enters into the citric acid cycle where it diffuses in the mitochondria. Glycolysis takes place in the cytosol of the cells of both prokaryotic and eukaryotic cells of the living organisms. Cytosol is the liquid component of the cytoplasm.