
In an aqueous solution of urea, the mole fraction of urea is 0.2. Calculate the mass % of solute.
Answer
581.1k+ views
Hint: Mole fraction can be simply defined as the number of moles of a specific solute compared to the total number of moles.
Formula to calculate mass percentage of solute is as follows.
Mass percentage of solute = \[\dfrac{\text{Mass of solute}}{\text{Mass of solution}}\times 100\]
Complete step by step answer:
In the question it is given that mole fraction of the urea in the aqueous solution is 0.2.
Means in the solution two chemicals are there, urea and water.
We have to calculate mass percentage of solute (urea).
Total number of moles is one.
Total number of moles = number of moles of urea (\[{{n}_{urea}}\]) + number moles of water (\[{{n}_{{{H}_{2}}O}}\])
${{n}_{urea}}+{{n}_{{{H}_{2}}O}}=1$
${{n}_{{{H}_{2}}O}}=1-0.2$
$\text{ = 0}\text{.8}$
We know that, mass percentage of solute = \[\dfrac{\text{mass of solute}}{\text{mass of solution}}\times 100\]
Mass of urea = mole fraction of urea × molecular weight of urea.
=$0.2\times 60$
=12
Mass of solvent = mole fraction water × molecular weight of water.
=$0.8\times 18$
=14.4
Mass of solution = mass of urea + mass of the solvent
= 12+14.4 = 26.4 gm.
Let’s calculate the mass percentage of solute or urea
=$\dfrac{12}{26.4}\times 100$
= 45.45%
Note: The solute is a chemical entity that is being dissolved, whereas the solvent is the dissolving medium. When solute dissolves into solvent, a solution is going to form. A solution is a homogeneous mixture containing a particular solute dissolved into a particular solvent.
Formula to calculate mass percentage of solute is as follows.
Mass percentage of solute = \[\dfrac{\text{Mass of solute}}{\text{Mass of solution}}\times 100\]
Complete step by step answer:
In the question it is given that mole fraction of the urea in the aqueous solution is 0.2.
Means in the solution two chemicals are there, urea and water.
We have to calculate mass percentage of solute (urea).
Total number of moles is one.
Total number of moles = number of moles of urea (\[{{n}_{urea}}\]) + number moles of water (\[{{n}_{{{H}_{2}}O}}\])
${{n}_{urea}}+{{n}_{{{H}_{2}}O}}=1$
${{n}_{{{H}_{2}}O}}=1-0.2$
$\text{ = 0}\text{.8}$
We know that, mass percentage of solute = \[\dfrac{\text{mass of solute}}{\text{mass of solution}}\times 100\]
Mass of urea = mole fraction of urea × molecular weight of urea.
=$0.2\times 60$
=12
Mass of solvent = mole fraction water × molecular weight of water.
=$0.8\times 18$
=14.4
Mass of solution = mass of urea + mass of the solvent
= 12+14.4 = 26.4 gm.
Let’s calculate the mass percentage of solute or urea
=$\dfrac{12}{26.4}\times 100$
= 45.45%
Note: The solute is a chemical entity that is being dissolved, whereas the solvent is the dissolving medium. When solute dissolves into solvent, a solution is going to form. A solution is a homogeneous mixture containing a particular solute dissolved into a particular solvent.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

State the laws of reflection of light

Name the metals and nonmetals in the first twenty class 11 chemistry CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

