
In a cricket match, a batswoman hits a boundary 6 out of 30 times she plays. Find the probability that she did not hit a boundary.
Answer
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Hint: The formula to find the probability is favourable outcomes divided by total outcomes. In this question we have the favourable condition as the number of boundaries hit and total condition is the total number of plays.
Complete step-by-step answer:
Number of times the batswoman hit a boundary = 6 (given)
Total ball she played = 30
Probability (hitting a boundary) = $\dfrac{6}{{30}} = \dfrac{1}{5}$
Probability of not hitting a boundary $ = 1 - \dfrac{1}{5} = \dfrac{4}{5}$
Note: Whenever we are supposed to find a probability of a condition that is the complete opposite of what asked like in this question they have given us the number of times the batswoman hits a boundary but asked us to find the probability of not hitting a boundary, find out the probability of hitting a boundary and then subtract it with 1, as the total probability is 1.
Complete step-by-step answer:
Number of times the batswoman hit a boundary = 6 (given)
Total ball she played = 30
Probability (hitting a boundary) = $\dfrac{6}{{30}} = \dfrac{1}{5}$
Probability of not hitting a boundary $ = 1 - \dfrac{1}{5} = \dfrac{4}{5}$
Note: Whenever we are supposed to find a probability of a condition that is the complete opposite of what asked like in this question they have given us the number of times the batswoman hits a boundary but asked us to find the probability of not hitting a boundary, find out the probability of hitting a boundary and then subtract it with 1, as the total probability is 1.
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