
If the S.P. of Rs. 24 results in a $20\% $ discount on list price, what S.P. would result in a $30\% $ discount on list price?
A) Rs.18
B) Rs.20
C) Rs.21
D) Rs.27
Answer
591.3k+ views
Hint:
We can take the list price as x. Then the discounted money will be equal to the given percentage of x. Then we can find the selling price in terms of x and equate it with the given selling price. Then we can solve for x, using the value of x, we can find the discount of at $30\% $ discount. Then we can subtract it from the list price to get the required selling price.
Complete step by step solution:
Let x be the list price of the object.
For a $20\% $ discount on list price, the discount will be $20\% $ of x. So, we can write,
${D_1} = 20\% x$
On converting percentage into fraction, we get,
$ \Rightarrow {D_1} = \dfrac{{20}}{{100}}x$
On cancelling the zeros, we get,
$ \Rightarrow {D_1} = \dfrac{2}{{10}}x$
We know that selling price is given by subtracting the discount price from the list price.
$ \Rightarrow {S_1} = x - {D_1}$
It is given that selling price is Rs. 24. On substitution, we get,
$ \Rightarrow 24 = x - \dfrac{{2x}}{{10}}$
On taking the LCM, we get,
$ \Rightarrow 24 = \dfrac{{10x - 2x}}{{10}}$
On simplification we get,
$ \Rightarrow 24 = \dfrac{{8x}}{{10}}$
On cross multiplication, we get,
$ \Rightarrow 8x = 24 \times 10$
On dividing throughout with 8, we get,
$ \Rightarrow x = \dfrac{{24 \times 10}}{8}$
On simplification, we get,
$ \Rightarrow x = 30$
Thus, the list price is Rs. 30.
Now we need to find the S.P when there is a $30\% $ discount on list price.
For a $30\% $ discount on list price, the discount will be $30\% $ of the list price. So, we can write,
${D_2} = 30\% x$
On converting percentage into fraction, we get,
$ \Rightarrow {D_2} = \dfrac{{30}}{{100}}x$
On cancelling the zeros, we get,
$ \Rightarrow {D_2} = \dfrac{3}{{10}}x$
On substituting the value of x, we get,
$ \Rightarrow {D_2} = \dfrac{3}{{10}} \times 30$
On further simplification, we get,
$ \Rightarrow {D_2} = 3 \times 3$
So, we have,
$ \Rightarrow {D_2} = 9$
We know that selling price is given by subtracting the discount price from the list price.
$ \Rightarrow {S_2} = x - {D_2}$
On substituting the values, we get,
$ \Rightarrow {S_2} = 30 - 9$
On simplification we get,
$ \Rightarrow {S_2} = 21$
So, the selling price when there is $30\% $ discount on list price is Rs. 21.
Therefore, the required solution is Rs.21.
So, the correct answer is option C.
Note:
Alternate solution is given by,
Let x be the list price of the object.
As the discount is $20\% $ , the selling price will be $80\% $ .
So, we can write,
$ \Rightarrow {S_1} = 80\% x$ .
On substitution of simplification, we get,
\[ \Rightarrow 24 = \dfrac{{80}}{{100}}x\]
On rearranging, we get,
\[ \Rightarrow x = \dfrac{{24 \times 100}}{{80}}\]
On further simplification,
\[ \Rightarrow x = 30\]
Now consider the case where discount is $30\% $
As the discount is $30\% $ , the selling price will be $70\% $ .
So, we can write,
\[ \Rightarrow {S_2} = 70\% x\] .
On substitution of simplification, we get,
\[ \Rightarrow {S_2} = \dfrac{{70}}{{100}} \times 30\]
On simplification, we get,
$ \Rightarrow {S_2} = 21$
So, the selling price when there is $30\% $ discount on list price is Rs. 21.
Therefore, the required solution is Rs.21.
We can take the list price as x. Then the discounted money will be equal to the given percentage of x. Then we can find the selling price in terms of x and equate it with the given selling price. Then we can solve for x, using the value of x, we can find the discount of at $30\% $ discount. Then we can subtract it from the list price to get the required selling price.
Complete step by step solution:
Let x be the list price of the object.
For a $20\% $ discount on list price, the discount will be $20\% $ of x. So, we can write,
${D_1} = 20\% x$
On converting percentage into fraction, we get,
$ \Rightarrow {D_1} = \dfrac{{20}}{{100}}x$
On cancelling the zeros, we get,
$ \Rightarrow {D_1} = \dfrac{2}{{10}}x$
We know that selling price is given by subtracting the discount price from the list price.
$ \Rightarrow {S_1} = x - {D_1}$
It is given that selling price is Rs. 24. On substitution, we get,
$ \Rightarrow 24 = x - \dfrac{{2x}}{{10}}$
On taking the LCM, we get,
$ \Rightarrow 24 = \dfrac{{10x - 2x}}{{10}}$
On simplification we get,
$ \Rightarrow 24 = \dfrac{{8x}}{{10}}$
On cross multiplication, we get,
$ \Rightarrow 8x = 24 \times 10$
On dividing throughout with 8, we get,
$ \Rightarrow x = \dfrac{{24 \times 10}}{8}$
On simplification, we get,
$ \Rightarrow x = 30$
Thus, the list price is Rs. 30.
Now we need to find the S.P when there is a $30\% $ discount on list price.
For a $30\% $ discount on list price, the discount will be $30\% $ of the list price. So, we can write,
${D_2} = 30\% x$
On converting percentage into fraction, we get,
$ \Rightarrow {D_2} = \dfrac{{30}}{{100}}x$
On cancelling the zeros, we get,
$ \Rightarrow {D_2} = \dfrac{3}{{10}}x$
On substituting the value of x, we get,
$ \Rightarrow {D_2} = \dfrac{3}{{10}} \times 30$
On further simplification, we get,
$ \Rightarrow {D_2} = 3 \times 3$
So, we have,
$ \Rightarrow {D_2} = 9$
We know that selling price is given by subtracting the discount price from the list price.
$ \Rightarrow {S_2} = x - {D_2}$
On substituting the values, we get,
$ \Rightarrow {S_2} = 30 - 9$
On simplification we get,
$ \Rightarrow {S_2} = 21$
So, the selling price when there is $30\% $ discount on list price is Rs. 21.
Therefore, the required solution is Rs.21.
So, the correct answer is option C.
Note:
Alternate solution is given by,
Let x be the list price of the object.
As the discount is $20\% $ , the selling price will be $80\% $ .
So, we can write,
$ \Rightarrow {S_1} = 80\% x$ .
On substitution of simplification, we get,
\[ \Rightarrow 24 = \dfrac{{80}}{{100}}x\]
On rearranging, we get,
\[ \Rightarrow x = \dfrac{{24 \times 100}}{{80}}\]
On further simplification,
\[ \Rightarrow x = 30\]
Now consider the case where discount is $30\% $
As the discount is $30\% $ , the selling price will be $70\% $ .
So, we can write,
\[ \Rightarrow {S_2} = 70\% x\] .
On substitution of simplification, we get,
\[ \Rightarrow {S_2} = \dfrac{{70}}{{100}} \times 30\]
On simplification, we get,
$ \Rightarrow {S_2} = 21$
So, the selling price when there is $30\% $ discount on list price is Rs. 21.
Therefore, the required solution is Rs.21.
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