# If $p\left( x \right) = {x^2} - 2\sqrt {2x} + 1$then $p\left( {2\sqrt 2 } \right)$ is equal to
$\begin{gathered} p\left( x \right) = {x^2} - 2\sqrt {2x} + 1 \\ p\left( {2\sqrt 2 } \right){\left( {2\sqrt 2 } \right)^2} - 2\sqrt 2 \left( {2\sqrt 2 } \right) + 1 \\ = 8 - 8 + 1 \\ = 1 \\ \end{gathered}$