Question

If p = -10, find the value of $$p^{2}-2p-100$$.

Answer 1

Hint: In this question it is given that the value of ‘p’ is -10, then we have to find the value of $$p^{2}-2p-100$$. So to find the solution we just need to put the value of ‘p’ in the given algebraic expression $$p^{2}-2p-100$$ whose result will give us the required solution.
Complete step-by-step solution:
Given, p = -10
Now we are going to put the value of ‘p’ in the given algebraic expression,
$$p^{2}-2p-100$$
$$=\left( -10\right)^{2} -2\left( -10\right) -100$$
$$=100+20-100$$ [since, $$\left( -10\right)^{2} $$ =100]
$$=20$$
Which is our required solution.
Note: While solving you have to remember that the square of any negative term always gives positive, i.e, $$\left( -10\right)^{2} =100$$ and also the product of a negative number by a negative number is always positive, i.e, (-2)(-10) = 20.