
If a, b and c are in AP then ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ will be in
a) GP
b) HP
c) AP
d) Sp
Answer
592.2k+ views
Hint: Since it is given that a, b and c are in AP, i.e. Arithmetic Progression. Therefore, we can write b as the arithmetic mean of a and c, i.e. $b=\dfrac{a+c}{2}$.
So, we get a relation between a, b and c. Now, take x raise to the power on both sides. We have: ${{x}^{b}}={{x}^{\dfrac{a+b}{2}}}$. Solve the equation to find the relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$.
Complete step by step answer:
As we know that, if three numbers are in Arithmetic Progression, the middle number can be written as the mean of the first and last number. Therefore, for the given numbers: a, b and c, we can write as:
$b=\dfrac{a+c}{2}......(1)$
Multiplying both sides with 2, we can write equation (1) as:
$2b=a+c......(2)$
So, we have a relation between a, b and c.
Now, take x raise to the power on both sides of equation (2), we get:
${{x}^{2b}}={{x}^{a+c}}......(3)$
As we know that:
$\left( \begin{align}
& {{x}^{2n}}={{\left( {{x}^{n}} \right)}^{2}} \\
& {{x}^{m+n}}={{x}^{m}}\times {{x}^{n}} \\
\end{align} \right)$
So, we can write equation (3) as:
${{\left( {{x}^{b}} \right)}^{2}}={{x}^{a}}\times {{x}^{c}}......(4)$
So, we get a relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$. Now, try to compare the given relation with different progressions.
According to AP, the middle number can be written as the mean of the first and last number. But in equation (4) the middle number is the square root of multiplication of the first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in AP.
Also, according to the GP, the middle number is the square root of multiplication of first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are in GP.
According to HP, the harmonic mean of three numbers is reciprocal of mean of reciprocal of first and last number, i.e. $b=\dfrac{2}{\dfrac{1}{a}+\dfrac{1}{c}}$ . So, it gives a complicated relation between a, b and c. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in HP.
So, the correct answer is “Option A”.
Note: Since Geometric progression deals with numbers having a common ratio as power. So do not choose this option deliberately. So, solve before choosing the option.
Always try to get a relation between what is given and what is asked. It makes it easier to find the answer.
So, we get a relation between a, b and c. Now, take x raise to the power on both sides. We have: ${{x}^{b}}={{x}^{\dfrac{a+b}{2}}}$. Solve the equation to find the relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$.
Complete step by step answer:
As we know that, if three numbers are in Arithmetic Progression, the middle number can be written as the mean of the first and last number. Therefore, for the given numbers: a, b and c, we can write as:
$b=\dfrac{a+c}{2}......(1)$
Multiplying both sides with 2, we can write equation (1) as:
$2b=a+c......(2)$
So, we have a relation between a, b and c.
Now, take x raise to the power on both sides of equation (2), we get:
${{x}^{2b}}={{x}^{a+c}}......(3)$
As we know that:
$\left( \begin{align}
& {{x}^{2n}}={{\left( {{x}^{n}} \right)}^{2}} \\
& {{x}^{m+n}}={{x}^{m}}\times {{x}^{n}} \\
\end{align} \right)$
So, we can write equation (3) as:
${{\left( {{x}^{b}} \right)}^{2}}={{x}^{a}}\times {{x}^{c}}......(4)$
So, we get a relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$. Now, try to compare the given relation with different progressions.
According to AP, the middle number can be written as the mean of the first and last number. But in equation (4) the middle number is the square root of multiplication of the first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in AP.
Also, according to the GP, the middle number is the square root of multiplication of first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are in GP.
According to HP, the harmonic mean of three numbers is reciprocal of mean of reciprocal of first and last number, i.e. $b=\dfrac{2}{\dfrac{1}{a}+\dfrac{1}{c}}$ . So, it gives a complicated relation between a, b and c. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in HP.
So, the correct answer is “Option A”.
Note: Since Geometric progression deals with numbers having a common ratio as power. So do not choose this option deliberately. So, solve before choosing the option.
Always try to get a relation between what is given and what is asked. It makes it easier to find the answer.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

