
If a, b and c are in AP then ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ will be in
a) GP
b) HP
c) AP
d) Sp
Answer
513.6k+ views
Hint: Since it is given that a, b and c are in AP, i.e. Arithmetic Progression. Therefore, we can write b as the arithmetic mean of a and c, i.e. $b=\dfrac{a+c}{2}$.
So, we get a relation between a, b and c. Now, take x raise to the power on both sides. We have: ${{x}^{b}}={{x}^{\dfrac{a+b}{2}}}$. Solve the equation to find the relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$.
Complete step by step answer:
As we know that, if three numbers are in Arithmetic Progression, the middle number can be written as the mean of the first and last number. Therefore, for the given numbers: a, b and c, we can write as:
$b=\dfrac{a+c}{2}......(1)$
Multiplying both sides with 2, we can write equation (1) as:
$2b=a+c......(2)$
So, we have a relation between a, b and c.
Now, take x raise to the power on both sides of equation (2), we get:
${{x}^{2b}}={{x}^{a+c}}......(3)$
As we know that:
$\left( \begin{align}
& {{x}^{2n}}={{\left( {{x}^{n}} \right)}^{2}} \\
& {{x}^{m+n}}={{x}^{m}}\times {{x}^{n}} \\
\end{align} \right)$
So, we can write equation (3) as:
${{\left( {{x}^{b}} \right)}^{2}}={{x}^{a}}\times {{x}^{c}}......(4)$
So, we get a relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$. Now, try to compare the given relation with different progressions.
According to AP, the middle number can be written as the mean of the first and last number. But in equation (4) the middle number is the square root of multiplication of the first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in AP.
Also, according to the GP, the middle number is the square root of multiplication of first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are in GP.
According to HP, the harmonic mean of three numbers is reciprocal of mean of reciprocal of first and last number, i.e. $b=\dfrac{2}{\dfrac{1}{a}+\dfrac{1}{c}}$ . So, it gives a complicated relation between a, b and c. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in HP.
So, the correct answer is “Option A”.
Note: Since Geometric progression deals with numbers having a common ratio as power. So do not choose this option deliberately. So, solve before choosing the option.
Always try to get a relation between what is given and what is asked. It makes it easier to find the answer.
So, we get a relation between a, b and c. Now, take x raise to the power on both sides. We have: ${{x}^{b}}={{x}^{\dfrac{a+b}{2}}}$. Solve the equation to find the relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$.
Complete step by step answer:
As we know that, if three numbers are in Arithmetic Progression, the middle number can be written as the mean of the first and last number. Therefore, for the given numbers: a, b and c, we can write as:
$b=\dfrac{a+c}{2}......(1)$
Multiplying both sides with 2, we can write equation (1) as:
$2b=a+c......(2)$
So, we have a relation between a, b and c.
Now, take x raise to the power on both sides of equation (2), we get:
${{x}^{2b}}={{x}^{a+c}}......(3)$
As we know that:
$\left( \begin{align}
& {{x}^{2n}}={{\left( {{x}^{n}} \right)}^{2}} \\
& {{x}^{m+n}}={{x}^{m}}\times {{x}^{n}} \\
\end{align} \right)$
So, we can write equation (3) as:
${{\left( {{x}^{b}} \right)}^{2}}={{x}^{a}}\times {{x}^{c}}......(4)$
So, we get a relation between ${{x}^{a}},{{x}^{b}},{{x}^{c}}$. Now, try to compare the given relation with different progressions.
According to AP, the middle number can be written as the mean of the first and last number. But in equation (4) the middle number is the square root of multiplication of the first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in AP.
Also, according to the GP, the middle number is the square root of multiplication of first and last number. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are in GP.
According to HP, the harmonic mean of three numbers is reciprocal of mean of reciprocal of first and last number, i.e. $b=\dfrac{2}{\dfrac{1}{a}+\dfrac{1}{c}}$ . So, it gives a complicated relation between a, b and c. So, ${{x}^{a}},{{x}^{b}},{{x}^{c}}$ are not in HP.
So, the correct answer is “Option A”.
Note: Since Geometric progression deals with numbers having a common ratio as power. So do not choose this option deliberately. So, solve before choosing the option.
Always try to get a relation between what is given and what is asked. It makes it easier to find the answer.
Recently Updated Pages
Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
Explain why it is said like that Mock drill is use class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

Net gain of ATP in glycolysis a 6 b 2 c 4 d 8 class 11 biology CBSE
