Question

Identify the rightmost representation in the multiplication of 101,102, 103 using Nikhilam method of Vedic method.
A) \[12\]
B) \[60\]
C) \[06\]
D) \[6\]

Answer 1

Hint: Algorithm of Nikhilam Sutra
Base value (B) has to be taken for the given numbers. This base value should be in powers of 10, 100, 100 according to the given multiplication.
Subtract or add the extra number which is closer to the base and write it in the LHS and RHS part.
The final product has two parts, one part is LHS and the other part is RHS divided by a vertical line for separation.
Complete step by step answer:
There, we need to find the multiplication of 101,102, 103 using the Nikhilam method of Vedic method.
the given numbers are closer to the base of \[100\].
We can represent the given numbers as:
\[
  101 = 100 + 1 \\
  102 = 100 + 2 \\
  103 = 100 + 3 \\
 \]

\[101\]	\[ + 1\]
\[102\]	\[ + 2\]
\[103\]	\[ + 3\]

Consider the numbers after 100 in the RHS. So the numbers will be 1, 2 and 3.
Now multiplying these numbers, we get, 6.
Since the base here is 100 we consider the answer as $06$ and not $6$.
So, we can say that the rightmost representation in the multiplication of 101,102, 103 using Nikhilam method of Vedic method \[06\].
Hence,
The correct option is (C) \[06\].

Note: Nikhilam Navatascaramam Dasatah Sutra is known as a Nikhilam Vedic Sutra which exactly means “all from 9 and last from 10”. In this method, the base value is considered in powers of 10. According to the number taken for multiplication, the nearest base value is also chosen. The base can be taken as 10, 100, 1000 so on as per the given numbers.
But the method has a drawback. This is suited for multiplication of numbers only nearer to the base value. If the number is far away from the base value this is also the same like normal multiplication.