
I. The pH of 1M NaOH is 13.
II. ${\text{pH + pOH = 14}}$.
a.) Statement I is true, Statement II is true and is a correct explanation of the phenomena described in I.
b.) Statement I is true; Statement II is false.
c.) Statement I is false; Statement II is true.
d.) Statement I is false; Statement II is false.
Answer
521.9k+ views
Hint: Knowing the pH of a compound, gives us an idea about whether the compound is acidic or basic. We should first know whether the statement I mentioned is correct or not. And then accordingly move to statement II.
Complete step by step solution: Examining statement I we get that,
Let us assume that 0.1 M of NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution.
Therefore,
$\eqalign{
& {\text{pOH = }} - \log \left[ {1 \times {{10}^{ - 1}}} \right] \cr
& = {\text{ }} - \log \left[ 1 \right]{\text{ + }} - \log \left[ {{{10}^{ - 1}}} \right] \cr
& = {\text{ 0 + 1 }} \times {\text{ 1}} \cr
& {\text{ = 0 + 1}} \cr
& {\text{ = 1}} \cr} $
Now we know that,
$\eqalign{
& {\text{pH + pOH = 14}} \cr
& {\text{pH + 1 = 14}} \cr
& {\text{pH = 14 }} - {\text{ 1}} \cr
& {\text{pH = 13 }} \cr} $
Therefore, the pH of 0.1 M NaOH solution is 13.
So, we can say that statement I is true, and statement II is true and is the correct explanation of the phenomena described in I.
Therefore, the correct answer to the question is Option A.
Additional Information: pH can also be defined as equal to the negative log base 10 of the concentration of protons in the solution.
Note: pOH is defined as the measure of the hydroxide ion or ${\text{O}}{{\text{H}}^ - }$ concentration. It is used to express the alkalinity of a solution.
High pH means the solution is basic in nature. High pOH means the solution is acidic in nature.
Complete step by step solution: Examining statement I we get that,
Let us assume that 0.1 M of NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution.
Therefore,
$\eqalign{
& {\text{pOH = }} - \log \left[ {1 \times {{10}^{ - 1}}} \right] \cr
& = {\text{ }} - \log \left[ 1 \right]{\text{ + }} - \log \left[ {{{10}^{ - 1}}} \right] \cr
& = {\text{ 0 + 1 }} \times {\text{ 1}} \cr
& {\text{ = 0 + 1}} \cr
& {\text{ = 1}} \cr} $
Now we know that,
$\eqalign{
& {\text{pH + pOH = 14}} \cr
& {\text{pH + 1 = 14}} \cr
& {\text{pH = 14 }} - {\text{ 1}} \cr
& {\text{pH = 13 }} \cr} $
Therefore, the pH of 0.1 M NaOH solution is 13.
So, we can say that statement I is true, and statement II is true and is the correct explanation of the phenomena described in I.
Therefore, the correct answer to the question is Option A.
Additional Information: pH can also be defined as equal to the negative log base 10 of the concentration of protons in the solution.
Note: pOH is defined as the measure of the hydroxide ion or ${\text{O}}{{\text{H}}^ - }$ concentration. It is used to express the alkalinity of a solution.
High pH means the solution is basic in nature. High pOH means the solution is acidic in nature.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

