How many triangles in a pentagram?
Answer
526.5k+ views
Hint: A pentagram which is also sometimes known by different names such as pentalpha, or star pentagon is the shape of a five-pointed polygon star. We will draw the figure of a pentagram and then try to count its number of triangles and then get our final answer.
Complete step-by-step answer:
A pentagram is in the shape of a five pointed polygon star, A figure of a pentagram is given below
There are five sides of the pentagram given above in the figure, the sides are namely,
$ FH,FI,JG,JH,IG $
The five sides overlap and cut each other to form a pentagonal star. The figure in middle $ ABCDE $ is the pentagon. We have to tell the number of triangles which are in the given figure. There are $ 10 $ isosceles triangles as each side of the pentagonal star is equal.
The triangle are,
$ FDE,JCD,IBC,HAB,GEA $ these are the triangles which are acute angle triangles. The other five obtuse angle triangles are listed below,
$ CFH,BJG,AIF,EHJ,DGI $
These are obtuse angle triangles thus in total we have $ 10 $ triangles (all isosceles) in a pentagram of which $ 5 $ are acute angled triangles and the rest are obtuse angled triangles.
Note: Some other facts about a pentagram,
A pentagram has $ 10 $ vertices. Five are the outer vertices of the star tips, the other five vertices are the vertices of the inner pentagon.
Each outer angle of the pentagram (For example $ \angle DFE $ ) is equal to $ {36^ \circ } $
The inner angles of the pentagram (angles of the pentagon) are of $ {108^ \circ } $
Complete step-by-step answer:
A pentagram is in the shape of a five pointed polygon star, A figure of a pentagram is given below
There are five sides of the pentagram given above in the figure, the sides are namely,
$ FH,FI,JG,JH,IG $
The five sides overlap and cut each other to form a pentagonal star. The figure in middle $ ABCDE $ is the pentagon. We have to tell the number of triangles which are in the given figure. There are $ 10 $ isosceles triangles as each side of the pentagonal star is equal.
The triangle are,
$ FDE,JCD,IBC,HAB,GEA $ these are the triangles which are acute angle triangles. The other five obtuse angle triangles are listed below,
$ CFH,BJG,AIF,EHJ,DGI $
These are obtuse angle triangles thus in total we have $ 10 $ triangles (all isosceles) in a pentagram of which $ 5 $ are acute angled triangles and the rest are obtuse angled triangles.
Note: Some other facts about a pentagram,
A pentagram has $ 10 $ vertices. Five are the outer vertices of the star tips, the other five vertices are the vertices of the inner pentagon.
Each outer angle of the pentagram (For example $ \angle DFE $ ) is equal to $ {36^ \circ } $
The inner angles of the pentagram (angles of the pentagon) are of $ {108^ \circ } $
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