
How do you solve \[4x+7=27\]?
Answer
564k+ views
Hint: In this problem, we have to solve the given equation and find the value of x. We can first subtract the number 7 on both the left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side. We can then divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
Complete step by step answer:
We know that the given equation to be solved to find the value of x is,
\[4x+7=27\]
We can first subtract the number 7 on both left-hand side and the right-hand side of the given equation and cancel similar terms on the left-hand side, we get
\[\begin{align}
& \Rightarrow 4x+7-7=27-7 \\
& \Rightarrow 4x=20 \\
\end{align}\]
We can now divide the number 4 on both the left-hand side and the right-hand side to get the value of x.
\[\Rightarrow \dfrac{4x}{4}=\dfrac{20}{4}\]
We can now cancel the similar terms on the left-hand side and use multiplication tables to can the terms on the right-hand side, we get
\[\Rightarrow x=5\]
Therefore, the value of x = 5.
Note: We can also check this value by substituting the resulted value in the given equation, we get
\[\begin{align}
& \Rightarrow 4\left( 5 \right)+7=27 \\
& \Rightarrow 20+7=27 \\
\end{align}\]
We can see that we got the same number on both the left-hand side and the right-hand side. Therefore, it is a correct value. Students make mistakes while using multiplication to simplify, we should know multiplication tables to solve these types of problems.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Trending doubts
What are gulf countries and why they are called Gulf class 8 social science CBSE

Name the states through which the Tropic of Cancer class 8 social science CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

Who created the image of Bharat Mata for the first class 8 social science CBSE


