Question

How do you solve 2a – 3 = -11 ?

Answer 1

Hint: This is a linear equation in one variable. We can convert this equation to an equation where in LHS only variable is present and in RHS only constant is present. In the equation 2a – 3 = -11 We can add 3 to both RHS and LHS to do so.

Complete step by step solution:
The given equation in the question is 2a – 3 = -11
Now we can bring all the a to LHS and all the constant to RHS, we can do that by adding 3 to both LHS and RHS
Adding 3 to both LHS and RHS we get 2a = -8 , we can see the coefficient of a is 2
So dividing LHS and RHS by 2 we get a = -4
So a = -4 is the solution of 2a – 3 = -11

Note: The equation given in the question was a linear equation in one variable, so one equation is enough to solve it. We can solve this question by drawing the graph of y = 2x – 3 and y = -11. Both the curves will form a straight line and the intersection point is the solution to the equation. In this case the intersection point will be at ( -4, -11). The point ( -4, -11) can satisfy both the equation y = 2x – 3 and y = -11.