Question

How do you factor $2{{x}^{2}}+5x+3$ ?

Answer 1

Hint: First to factorize this given polynomial we must split the middle term. To split the middle term, we use the sum and product form. Now take-out common terms from the first two terms and last two terms. Then write them together as the product of sums form. Now represent them as the factors of the given expression.

Complete step by step solution:
The given polynomial which must be factorized is $2{{x}^{2}}+5x+3$
To factorize this polynomial, we must first split the middle term.
For this, we use the product sum form.
If the polynomial’s general form is $a{{x}^{2}}+bx+c=0$
Then to split the middle term, we use the product and sum formula.
Which is,
The product of the middle terms after splitting must be $a\times c$
And the sum of the middle terms must be $b$
Here $a=2;b=5;c=3$
The product of the terms is $2\times 3=6$
The sum of the terms is $5$
Therefore, the terms can be $2x,3x\;$
On substituting back, we get,
$\Rightarrow 2{{x}^{2}}+2x+3x+3$
The polynomial is of degree $2$
Now, firstly let us take the common terms out of the first two terms.
$\Rightarrow 2x\left( x+1 \right)+3x+3$
Now secondly take the common terms out of the last two terms.
$\Rightarrow 2x\left( x+1 \right)+3\left( x+1 \right)$
Now on writing it in the form of the product of sums, also known as factoring,
$\Rightarrow \left( 2x+3 \right)\left( x+1 \right)$
Now writing all the factors together we get,
$\Rightarrow \left( x+1 \right)\left( 2x+3 \right)$

Hence the factors for the polynomial $2{{x}^{2}}+5x+3$ are $\left( x+1 \right)\left( 2x+3 \right)$.

Note: The process of factorization is the reverse multiplication. In the above question, we have multiplied two linear line equations to get a quadratic equation (a polynomial of degree $2$) expression using the distributive law. The name quadratic comes from “quad” meaning square because the variable gets squared. Also known as a polynomial of degree $2$