How do you factor $16{x^4} - 81{y^4}$?
Answer
570.3k+ views
Hint: In this question we need to find the factor of algebraic expression $16{x^4} - 81{y^4}$. Given algebraic expression is of two variables $x$ and $y$. To solve this question we need to use the following basic algebraic identities such as ${a^2} - {b^2} = (a + b)(a - b)$. To solve this question we need to know the square root of a number or how to find the square root of a number. To solve this we also need to know the laws of exponents.
Complete step by step solution:
Let us try to solve this question in which we are asked to find the factor of the given algebraic expression $16{x^4} - 81{y^4}$. To find the factors of the equation we manipulate the given algebraic expression by using our knowledge of exponents, so that we can apply the algebraic identity ${a^2} - {b^2} = (a + b)(a - b)$. So, let’s come back to the question.
We have to find factor of $16{x^4} - 81{y^4}$, this can be written as
$16{x^4} - 81{y^4} = {(4{x^2})^2} - {(9{y^2})^2}$ $(1)$
Because we know that from law of exponents ${a^{b \cdot c}} = {({a^b})^c}$ and also we know that $16 = {4^2}$ and $81 = {9^2}$
Now, applying the identity ${a^2} - {b^2} = (a + b)(a - b)$ in equation $(1)$, we get
${(4{x^2})^2} - {(9{x^2})^2} = (4{x^2} - 9{x^2})(4{x^2} + 9{y^2})$ $(2)$
Now, again applying the identity ${a^2} - {b^2} = (a + b)(a - b)$ in equation (2), we get
$(4{x^2} - 9{x^2})(4{x^2} + 9{y^2}) = (2x - 3y)(2x + 3y)(4{x^2} + 9{y^2})$ $(3)$
Equation $(3)$ cannot be further factorized because this equation has no more linear factors.
Hence the factor of algebraic expression $16{x^4} - 81{y^4} = (2x - 3y)(2x + 3y)(4{x^2} + 9{y^2})$.
Note: For solving this type of question in which we are asked to find the factor of algebraic expression having the knowledge of some basic algebraic identities are must such as ${a^2} - {b^2} = (a + b)(a - b)$,
${(a + b)^2} = {a^2} + 2ab + {b^2}$ etc.
To solve these types of questions we just have to break the expression using knowledge of exponents and apply known algebraic identities.
Complete step by step solution:
Let us try to solve this question in which we are asked to find the factor of the given algebraic expression $16{x^4} - 81{y^4}$. To find the factors of the equation we manipulate the given algebraic expression by using our knowledge of exponents, so that we can apply the algebraic identity ${a^2} - {b^2} = (a + b)(a - b)$. So, let’s come back to the question.
We have to find factor of $16{x^4} - 81{y^4}$, this can be written as
$16{x^4} - 81{y^4} = {(4{x^2})^2} - {(9{y^2})^2}$ $(1)$
Because we know that from law of exponents ${a^{b \cdot c}} = {({a^b})^c}$ and also we know that $16 = {4^2}$ and $81 = {9^2}$
Now, applying the identity ${a^2} - {b^2} = (a + b)(a - b)$ in equation $(1)$, we get
${(4{x^2})^2} - {(9{x^2})^2} = (4{x^2} - 9{x^2})(4{x^2} + 9{y^2})$ $(2)$
Now, again applying the identity ${a^2} - {b^2} = (a + b)(a - b)$ in equation (2), we get
$(4{x^2} - 9{x^2})(4{x^2} + 9{y^2}) = (2x - 3y)(2x + 3y)(4{x^2} + 9{y^2})$ $(3)$
Equation $(3)$ cannot be further factorized because this equation has no more linear factors.
Hence the factor of algebraic expression $16{x^4} - 81{y^4} = (2x - 3y)(2x + 3y)(4{x^2} + 9{y^2})$.
Note: For solving this type of question in which we are asked to find the factor of algebraic expression having the knowledge of some basic algebraic identities are must such as ${a^2} - {b^2} = (a + b)(a - b)$,
${(a + b)^2} = {a^2} + 2ab + {b^2}$ etc.
To solve these types of questions we just have to break the expression using knowledge of exponents and apply known algebraic identities.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

