
How do you add $\sqrt{2}+\sqrt{2}$ ?
Answer
556.2k+ views
Hint: To solve these type of questions, we should know about irrational numbers and the property of addition of irrational numbers (which is that they can be simply added just like variables).
Complete Step by Step Solution:
First of all, we should know what is an irrational number, An irrational number is a number that cannot be expressed as a fraction ${}^{p}/{}_{q}$ for any integers $p$ and $q$. Irrational numbers have decimal expansions that neither terminate nor become periodic.
Now, as we know irrational numbers can be added just like variables $\left( a+a \right)=2a$
Similarly, we can write
$\sqrt{2}+\sqrt{2}=2\sqrt{2}$
Hence we will get the solution as $2\sqrt{2}$.
Note:
1) An irrational number is a number that cannot be expressed as a fraction ${}^{p}/{}_{q}$ for any integers $p$ and $q$.
2) Irrational numbers have decimal expansions that neither terminate nor become periodic.
Complete Step by Step Solution:
First of all, we should know what is an irrational number, An irrational number is a number that cannot be expressed as a fraction ${}^{p}/{}_{q}$ for any integers $p$ and $q$. Irrational numbers have decimal expansions that neither terminate nor become periodic.
Now, as we know irrational numbers can be added just like variables $\left( a+a \right)=2a$
Similarly, we can write
$\sqrt{2}+\sqrt{2}=2\sqrt{2}$
Hence we will get the solution as $2\sqrt{2}$.
Note:
1) An irrational number is a number that cannot be expressed as a fraction ${}^{p}/{}_{q}$ for any integers $p$ and $q$.
2) Irrational numbers have decimal expansions that neither terminate nor become periodic.
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