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# Give simple chemical test to distinguish between the following pair of compoundsi.Ethanal and propanalii.Benzoic acid and phenol

Last updated date: 20th Mar 2023
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Hint: We have to remember that the ethanal is an organic compound and it is also known as acetaldehyde having the formula, $C{H_3}CHO$. And the propanal is also an aldehyde which is known as propionaldehyde having the formula, $C{H_3}C{H_2}CHO$. Benzoic acid is an organic compound with the chemical formula, ${C_6}{H_5}COOH$. And phenol is an aromatic organic compound having the formula, ${C_6}{H_5}OH$.

$C{H_3}CHO + 4NaOH + 3{I_2} \to 3C{H_3}I + HCOONa + 3NaI + 3{H_2}O$
$C{H_3}C{H_2}CHO + 4NaOH + 3{I_2} \to No\,reaction$
(ii) Benzoic acid and phenol can be distinguished by sodium bicarbonate test. Benzoic acid gives sodium bicarbonate test. When benzoic acid reacts in sodium bicarbonate, there is a formation of brisk effervescence by evolving $C{O_2}$ gas. And the reaction can be written as,
We have to remember that the ethanal and propanal can be distinguished by iodoform test. Propanal will not give the iodoform test and it will not give any yellow precipitate but ethanal gives a yellow precipitate which is methyl iodide, $C{H_3}I$. And benzoic acid and phenol can be distinguished by using sodium bicarbonate tests. Benzoic acid gives brisk effervescence by evolving $C{O_2}$ gas but Phenol does not give a positive result for sodium bicarbonate test.