
For the reaction equilibrium $2NOB{r_{(g)}} \rightleftarrows 2N{O_{(g)}} + B{r_{2(g)}}$ , if ${P_{B{r_2}}} = \dfrac{P}{9}$ at equilibrium and P is the initial total pressure, then the ratio $\dfrac{{{K_P}}}{P}$ is equal to:
A.$\dfrac{1}{9}$
B.$\dfrac{4}{{441}}$
C.$\dfrac{1}{{27}}$
D.$\dfrac{1}{3}$
Answer
510.3k+ views
Hint: We have to know that, in a chemical reaction, compound equilibrium is the state where both the reactants and items are available in focuses, which have no further propensity to change with time, so that there is no detectable change in the properties of the framework. This state results when the forward reaction continues at a similar rate as the converse reaction.
Complete answer:
We have to know that the unique harmony states that the reaction rate of the forward and in reverse reactions are for the most part not zero, however they are equivalent. Along these lines, there are no net changes in the convergences of the reactants and items.
Balance can be comprehensively delegated heterogeneous and homogeneous harmony. Homogeneous harmony comprises reactants and items having a place in a similar stage though heterogeneous balance becomes an integral factor for reactants and items in various stages.
The given equilibrium chemical reaction has to be given below,
$2NOB{r_{(g)}} \rightleftharpoons 2N{O_{(g)}} + B{r_{2(g)}}$
Where,
The partial pressure of bromine, the partial pressure of $NOBr$ and $NO$ are also given below,
${P_{B{r_2}}} = \dfrac{P}{9}$
Then,
${P_{NOBr}} = \dfrac{{7P}}{9}$ and ${P_{NO}} = \dfrac{{2P}}{9}$
These values are substituted by the equilibrium constant expression.
The formula of equilibrium constant expression is,
${K_P} = \dfrac{{P_{NO}^2.{P_{B{r_2}}}}}{{P_{NOBr}^2}} = \dfrac{{{{\left( {\dfrac{{2P}}{9}} \right)}^2}\left( {\dfrac{P}{9}} \right)}}{{{{\left( {\dfrac{{7P}}{9}} \right)}^2}}}$
Therefore,
$\dfrac{{{K_P}}}{P} = \dfrac{4}{{441}}$
Hence, the correct option is (B).
Note:
We have to know that, an illustration of balance is the point at which you are quiet and consistent. An illustration of harmony is when hot air and cold air are going into the room simultaneously with the goal that the general temperature of the room doesn't change by any means.
Complete answer:
We have to know that the unique harmony states that the reaction rate of the forward and in reverse reactions are for the most part not zero, however they are equivalent. Along these lines, there are no net changes in the convergences of the reactants and items.
Balance can be comprehensively delegated heterogeneous and homogeneous harmony. Homogeneous harmony comprises reactants and items having a place in a similar stage though heterogeneous balance becomes an integral factor for reactants and items in various stages.
The given equilibrium chemical reaction has to be given below,
$2NOB{r_{(g)}} \rightleftharpoons 2N{O_{(g)}} + B{r_{2(g)}}$
Where,
The partial pressure of bromine, the partial pressure of $NOBr$ and $NO$ are also given below,
${P_{B{r_2}}} = \dfrac{P}{9}$
Then,
${P_{NOBr}} = \dfrac{{7P}}{9}$ and ${P_{NO}} = \dfrac{{2P}}{9}$
These values are substituted by the equilibrium constant expression.
The formula of equilibrium constant expression is,
${K_P} = \dfrac{{P_{NO}^2.{P_{B{r_2}}}}}{{P_{NOBr}^2}} = \dfrac{{{{\left( {\dfrac{{2P}}{9}} \right)}^2}\left( {\dfrac{P}{9}} \right)}}{{{{\left( {\dfrac{{7P}}{9}} \right)}^2}}}$
Therefore,
$\dfrac{{{K_P}}}{P} = \dfrac{4}{{441}}$
Hence, the correct option is (B).
Note:
We have to know that, an illustration of balance is the point at which you are quiet and consistent. An illustration of harmony is when hot air and cold air are going into the room simultaneously with the goal that the general temperature of the room doesn't change by any means.
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