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For given reaction,
CaCO3+2HClCaCl2+H2O+CO2
The volume of CO2 gas formed when 2.5g calcium carbonate is dissolved in excess hydrochloric acid at 0C and 1atm pressure is:
[1 mole of any gas at 0C and 1atm pressure occupies 22.414L volume]
A) 1.12L
B) 56.0L
C) 0.28L
D) 0.56L

Answer
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Hint: We perceive the volume involved by one mole of substance at a given temperature and weight is called molar volume. It is routinely valuable to the gases where the idea of the gas doesn't influence the volume. The most widely recognized representation is that the molar volume of gas at standard temperature-pressure condition is equivalent to 22.4L for one mole of an ideal gas at temperature equivalent to 273K and pressure equivalent to 1atm.

Complete step by step answer:
The reaction is CaCO3+2HClCaCl2+H2O+CO2
We are on familiar terms with that, At STP, 1 mole of a gas occupies 22.4L of volume.
Thus volume of carbon dioxide formed from 2.5gCaCO3 can be calculated as,
Volume=2.5×22.4100=0.56L
Thus the volume of carbon dioxide formed from 2.5gCaCO3 is 0.56L.
Therefore, the option (D) is correct.

Additional information:
We realize that, Vapor density is the proportion of the mass of a volume of a gas, to the mass of an equivalent volume of hydrogen, estimated under the standard states of temperature and pressure.
Vapour density=Mass of n molecules of gasMass of n molecule of hydrogen
First, we have to calculate the molar mass of a gas using the relation.
Molar Mass=2×vapor density
If the given vapor density of the gas is 11.2.
Thus, the molar mass of the gas is calculated as,
Molar Mass=2×11.2=22.4gm/mole
Next, we have to calculate the number of moles of the gas.
Let us assume that the given amount of the gas is 24gm.
Therefore the number of moles of the gas is given by,
Number Of Moles=2.422.4mole=0.1071moles
We are on familiar terms with that, At STP, 1 mole of a gas occupies 22.4L of volume. Here, we have about 0.1071moles of the gas. Hence, the volume of gas filled at STP is,
Volume Occupied=0.1071×22.4L=2.4L
Thus, 24g of a gas, with a vapor density of 11.2, will occupy 2.4L of volume at STP.

Note:
Now we can see the difference between atmosphere and NTP:
Standard temperature and pressure conditions are thought of as STP. The quality temperature value is 0C and the standard pressure value is 100kPa or 1bar Normal Temperature and Pressure is known as NTP the worth of pressure at NTP is 101.325kPa and the temperature at NTP is 20C.