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# How do you find the square root of $-59$?

Last updated date: 20th Jul 2024
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Hint: We first try to form the imaginary numbers for $-59$ using the identities ${{i}^{2}}=-1,{{i}^{3}}=-i,{{i}^{4}}=1$. Then we get the root value in the form of both positive and negative values and imaginary numbers. We also find the decimal value for $\sqrt{59}$.

The square root value of the negative value gives imaginary values.
Therefore, we use the know identity values and relations for imaginary $i=\sqrt{-1}$ where ${{i}^{2}}=-1,{{i}^{3}}=-i,{{i}^{4}}=1$.
Therefore, $-59=\left( -1 \right)\times 59=59{{i}^{2}}$.
Now taking the root value we get $\sqrt{-59}=\sqrt{59{{i}^{2}}}=\pm i\sqrt{59}$.
We can also find the root value in decimal for 59 as 59 is a prime number.
We take 2 digits as a set from the right end and complete the division. For decimal form we take the set from the right side of the decimal.
\begin{align} & 7 \\ & 7\left| \!{\overline {\, \begin{align} & \overline{59}.\overline{00}\overline{00} \\ & \underline{49} \\ & 10.00 \\ \end{align} \,}} \right. \\ \end{align}
Now we have to enter the decimal part. We keep doing the breaking in the set form till 3-digit place after decimal.
\begin{align} & 7.67 \\ & 146\left| \!{\overline {\, \begin{align} & 1000\overline{00} \\ & \underline{876} \\ & 12400 \\ \end{align} \,}} \right. \\ & 1527\left| \!{\overline {\, \begin{align} & 12400 \\ & \underline{10689} \\ & 1711 \\ \end{align} \,}} \right. \\ \end{align}
So, $\sqrt{-59}=\pm i\sqrt{59}=\pm 7.67i$
Therefore, the square root of $-59$ is $\pm i\sqrt{59}=\pm 7.67i$.
So, the correct answer is “$\pm 7.67i$”.

Note: The long-division method and arranging the set of 2 digits is different for integer and decimal. But taking double for the next division and putting a particular number is the same process for both of them. Since 3 is a non-perfect square number, we will find the value of root 3 using the long division method as shown above.