
Find the perimeter of the below figure.
Answer
468.9k+ views
Hint: We are given a figure with nine sides and asked for its perimeter. The length of each side is given in the figure. Perimeter of any object is the distance around the shape of that object. Now to find the perimeter of the given polygon we just need to add the lengths of all the sides.
Complete step-by-step answer:
We can see from the figure that the given polygon has nine sides
Let's give a name to each side and write down its measurements.
We have named the sides in the diagram and now let’s write down the measurements
The length of side $AB$ is $12cm$
The length of side $BC$ is $2cm$
The length of side $CD$ is $3cm$
The length of side $DE$ is $8cm$
The length of side $EF$ is $5cm$
The length of side $FG$ is $4cm$
The length of side $GH$ is $4cm$
The length of side $HI$ is $6cm$
The length of side $IA$ is $5cm$
Now we have a clear picture of the measurement of the sides.
The perimeter is just the boundary of the given polygon; hence it can be found by adding up the length of all the sides.
That is, the sum of the length of the sides gives the perimeter of the given polygon.
So now let’s add all the lengths of the sides
Perimeter $ = AB + BC + CD + DE + EF + FG + GH + HI + IA$
Perimeter= $12 + 2 + 3 + 8 + 5 + 4 + 4 + 6 + 5 = 49cm$
Therefore, we get the perimeter of the given polygon to be $49cm$.
Note: Here, The given polygon is an irregular polygon, we have a formula for perimeter for regular polygons like square, rectangle, etc. There is no particular formula to find the perimeter of an irregular shape. The logic is to add all side lengths to get the perimeter.
Complete step-by-step answer:
We can see from the figure that the given polygon has nine sides
Let's give a name to each side and write down its measurements.
We have named the sides in the diagram and now let’s write down the measurements
The length of side $AB$ is $12cm$
The length of side $BC$ is $2cm$
The length of side $CD$ is $3cm$
The length of side $DE$ is $8cm$
The length of side $EF$ is $5cm$
The length of side $FG$ is $4cm$
The length of side $GH$ is $4cm$
The length of side $HI$ is $6cm$
The length of side $IA$ is $5cm$
Now we have a clear picture of the measurement of the sides.
The perimeter is just the boundary of the given polygon; hence it can be found by adding up the length of all the sides.
That is, the sum of the length of the sides gives the perimeter of the given polygon.
So now let’s add all the lengths of the sides
Perimeter $ = AB + BC + CD + DE + EF + FG + GH + HI + IA$
Perimeter= $12 + 2 + 3 + 8 + 5 + 4 + 4 + 6 + 5 = 49cm$
Therefore, we get the perimeter of the given polygon to be $49cm$.
Note: Here, The given polygon is an irregular polygon, we have a formula for perimeter for regular polygons like square, rectangle, etc. There is no particular formula to find the perimeter of an irregular shape. The logic is to add all side lengths to get the perimeter.
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