Question

Find the mean of the first six multiples of 4?
(a) 13.5
(b) 14.5
(c) 14
(d) 16

Answer 1

Hint: We start solving the problem by calculating the first six multiples of 4 by multiplying 4 with the integers 1, 2, 3, 4, 5 and 6 respectively. We then substitute the obtained values in the formula of mean of n numbers ${\displaystyle \frac{a_1+a_2+......+a_n}{n}}$ and make necessary calculations to get the required value of the mean of the numbers.

Complete step by step answer:
According to the problem, we need to find the mean of the first six multiples of 4.
Let us first find the six multiples of 4 and then find the mean of those numbers.
We know that the first six multiples of 4 are found by multiplying 4 with 1, 2, 3, 4, 5, 6.
So, we get $$4\times 1=4$$.
$\Rightarrow 4\times 2=8$.
$\Rightarrow 4\times 3=12$.
$\Rightarrow 4\times 4=16$.
$\Rightarrow 4\times 5=20$.
$\Rightarrow 4\times 6=24$.
So, we have found the first six multiples of 4 as 4, 8, 12, 16, 20, 24.
Now, let us find the mean of the obtained numbers 4, 8, 12, 16, 20, 24. Let us assume it as m.
We know that the mean of the numbers $a_1$, $a_2$,……, $a_n$ is ${\displaystyle \frac{a_1+a_2+......+a_n}{n}}$.
So, we get mean (m) = ${\displaystyle \frac{4+8+12+16+20+24}{6}}$.
$\Rightarrow$ mean (m) = ${\displaystyle \frac{84}{6}}$.
$\Rightarrow$ mean (m) = $14$.
So, we have found the mean of the first six multiples of 4 as 14.
∴ The mean of the first six multiples of 4 is 14.

So, the correct answer is “Option C”.

Note: We should not consider negative integers or zero while taking the integral multiples of 4, as the multiples are always assumed to start with the integer 1 and move forwards. We should consider multiplying 4 with 0 or negative integers or fractions if it is mentioned in the problem. We can also solve this problem by finding the mean of the numbers 1, 2, 3, 4, 5 and 6 first and then multiplying this mean with 4.