Answer
384.3k+ views
Hint: Here in the question we are supposed to find the inverse trigonometric function to find the angle. This means the value in the bracket of trigonometric functions given here is an exact value of the function at a certain angle. So we have to find that angle in this question. For that we will see the range for Cosecant and then check for the principal values of trigonometric functions.
Complete step by step solution:
Let us suppose that $y = {\csc ^{ - 1}}( - 1)$ ----equation (1)
As we can see we have converted this into an equation by putting two expressions on both sides of the sign ‘equals to’ (=).
We can compare equation (1) with this equation: $y = \;f(x)$ -----equation (2)
From equation (1) & (2) we have: \[f(x) = {\csc ^{ - 1}}( - 1)\]
This means we can operate on equation (1) and shift the inverse trigonometric function on the LHS.
$ \Rightarrow \csc y = - 1$----equation (3)
We know that
\[\csc {90^ \circ } = 1\]
Since $\csc y$ is negative in equation (3) so we have to recall the signs of trigonometric functions in all the quadrants which is given in figure given below
From figure (a) we can certainly say that $\sin y$ is positive in 1 st & 2 nd quadrant and similarly $\csc y$ will be positive in the same because both are reciprocal ratios of a triangle i.e. $\sin y = \dfrac{1}{{\csc y}}$ which means it has to be negative in 3 rd and 4 th quadrants.
So the value of $\csc y$ in 3 rd quadrant:
${180^ \circ } + {90^ \circ } = \;{270^ \circ }$
Similarly, the value of $\cot y$ in 4 th quadrant:
${360^\circ } - {90^ \circ } = {270^ \circ }$
From this we can find the value of the equation (3)
\[
\Rightarrow \csc y = - \;1 \\
\Rightarrow \;y = \;{270^ \circ } \\
\]
To convert these degree values into radian values we have to multiply it by $\dfrac{\pi }{{180}}$i.e.
$
y = 270^\circ \\
y = 270 \times \dfrac{\pi }{{180}} \\
y = \dfrac{{3\pi }}{2} \\
$
But we have to find the exact value of the given inverse function for that we check for the range of inverse function cotangent i.e.
$
{\csc ^{ - 1}}(b) = \theta \;;\;where\;\theta \in \;[ - \dfrac{\pi }{2},\dfrac{\pi }{2}] - \{ 0\} $
From this we can say that
$
{\csc ^{ - 1}}( - 1) = \dfrac{{3\pi }}{2} = - \dfrac{\pi }{2}{\text{ because}} - \dfrac{\pi }{2} \in [ -
\dfrac{\pi }{2},\dfrac{\pi }{2}] - \{ 0\} \\
\Rightarrow y = - \dfrac{\pi }{2}\; \\
$
Note: We can find angles of trigonometric functions in the manner given above but the important part is to check the range of these inverse trigonometric functions in order to find the exact solution. Changing degree values of angles into radians is not necessary but angles in radians are more preferable at this level.
Complete step by step solution:
Let us suppose that $y = {\csc ^{ - 1}}( - 1)$ ----equation (1)
As we can see we have converted this into an equation by putting two expressions on both sides of the sign ‘equals to’ (=).
We can compare equation (1) with this equation: $y = \;f(x)$ -----equation (2)
From equation (1) & (2) we have: \[f(x) = {\csc ^{ - 1}}( - 1)\]
This means we can operate on equation (1) and shift the inverse trigonometric function on the LHS.
$ \Rightarrow \csc y = - 1$----equation (3)
We know that
\[\csc {90^ \circ } = 1\]
Since $\csc y$ is negative in equation (3) so we have to recall the signs of trigonometric functions in all the quadrants which is given in figure given below
![seo images](https://www.vedantu.com/question-sets/2b2196f8-3ee1-4eac-ad25-240336e9ea644444416187148141066.png)
From figure (a) we can certainly say that $\sin y$ is positive in 1 st & 2 nd quadrant and similarly $\csc y$ will be positive in the same because both are reciprocal ratios of a triangle i.e. $\sin y = \dfrac{1}{{\csc y}}$ which means it has to be negative in 3 rd and 4 th quadrants.
So the value of $\csc y$ in 3 rd quadrant:
${180^ \circ } + {90^ \circ } = \;{270^ \circ }$
Similarly, the value of $\cot y$ in 4 th quadrant:
${360^\circ } - {90^ \circ } = {270^ \circ }$
From this we can find the value of the equation (3)
\[
\Rightarrow \csc y = - \;1 \\
\Rightarrow \;y = \;{270^ \circ } \\
\]
To convert these degree values into radian values we have to multiply it by $\dfrac{\pi }{{180}}$i.e.
$
y = 270^\circ \\
y = 270 \times \dfrac{\pi }{{180}} \\
y = \dfrac{{3\pi }}{2} \\
$
But we have to find the exact value of the given inverse function for that we check for the range of inverse function cotangent i.e.
$
{\csc ^{ - 1}}(b) = \theta \;;\;where\;\theta \in \;[ - \dfrac{\pi }{2},\dfrac{\pi }{2}] - \{ 0\} $
From this we can say that
$
{\csc ^{ - 1}}( - 1) = \dfrac{{3\pi }}{2} = - \dfrac{\pi }{2}{\text{ because}} - \dfrac{\pi }{2} \in [ -
\dfrac{\pi }{2},\dfrac{\pi }{2}] - \{ 0\} \\
\Rightarrow y = - \dfrac{\pi }{2}\; \\
$
Note: We can find angles of trigonometric functions in the manner given above but the important part is to check the range of these inverse trigonometric functions in order to find the exact solution. Changing degree values of angles into radians is not necessary but angles in radians are more preferable at this level.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)