
Find the coordinates of the centroid of the triangle if point D (-7, 6), E (5, 8) and F (2, -2) are the midpoints of the sides of that triangle.
Answer
593.1k+ views
Hint: We will use the very important concept that if we have a triangle ABC and D, E and F are the midpoints of BC, CA and AB respectively, then centroid of triangle ABC coincides with the centroid of triangle DEF by using the centroid formula which is as follows:
If \[\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right),\left( {{x}_{3}},{{y}_{3}} \right)\] are the vertices of triangle, then the centroid of triangle is \[\left( \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3},\dfrac{{{y}_{1}}+{{y}_{2}}+{{y}_{3}}}{3} \right)\]
Complete step-by-step answer:
We have been given the midpoint of sides of the triangle as D (-7, 6), E (5, 8) and F (2, -2).
Let us suppose the triangle to be ABC and D, E and F are the midpoints of BC, AC and AB.
Now we know that if we have any triangle ABC and their midpoint’s area D, E and F then the centroid of triangle ABC coincides with the centroid of triangle DEF.
So we will find the centroid of triangle DEF which gives the centroid of triangle ABC.
We know that if \[\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right),\left( {{x}_{3}},{{y}_{3}} \right)\] are the vertices of the triangle, then,
X coordinate of centroid \[=\dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}\]
Y coordinate of centroid \[=\dfrac{{{y}_{1}}+{{y}_{2}}+{{y}_{3}}}{3}\]
We have D (-7, 6), E (5, 8) and F (2, -2)
X coordinate of centroid of triangle DEF \[=\dfrac{-7+5+2}{3}=\dfrac{0}{3}=0\]
Y coordinate of centroid of triangle DEF \[=\dfrac{6+8+(-2)}{3}=\dfrac{14-2}{3}=\dfrac{12}{3}=4\]
So the coordinates of the centroid of the triangle DEF are (0, 4)
Hence the coordinates of the centroid of the triangle ABC are (0, 4).
Note: Be careful while finding the values of the coordinates of the centroid and also take care of the sign while substituting the values of coordinates of the given midpoints. Also, remember that the centroid of a triangle is a point where all the three medians of the triangle intersect and the median is a line that joins the midpoint of a side and the opposite vertex of a triangle.
If \[\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right),\left( {{x}_{3}},{{y}_{3}} \right)\] are the vertices of triangle, then the centroid of triangle is \[\left( \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3},\dfrac{{{y}_{1}}+{{y}_{2}}+{{y}_{3}}}{3} \right)\]
Complete step-by-step answer:
We have been given the midpoint of sides of the triangle as D (-7, 6), E (5, 8) and F (2, -2).
Let us suppose the triangle to be ABC and D, E and F are the midpoints of BC, AC and AB.
Now we know that if we have any triangle ABC and their midpoint’s area D, E and F then the centroid of triangle ABC coincides with the centroid of triangle DEF.
So we will find the centroid of triangle DEF which gives the centroid of triangle ABC.
We know that if \[\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right),\left( {{x}_{3}},{{y}_{3}} \right)\] are the vertices of the triangle, then,
X coordinate of centroid \[=\dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}\]
Y coordinate of centroid \[=\dfrac{{{y}_{1}}+{{y}_{2}}+{{y}_{3}}}{3}\]
We have D (-7, 6), E (5, 8) and F (2, -2)
X coordinate of centroid of triangle DEF \[=\dfrac{-7+5+2}{3}=\dfrac{0}{3}=0\]
Y coordinate of centroid of triangle DEF \[=\dfrac{6+8+(-2)}{3}=\dfrac{14-2}{3}=\dfrac{12}{3}=4\]
So the coordinates of the centroid of the triangle DEF are (0, 4)
Hence the coordinates of the centroid of the triangle ABC are (0, 4).
Note: Be careful while finding the values of the coordinates of the centroid and also take care of the sign while substituting the values of coordinates of the given midpoints. Also, remember that the centroid of a triangle is a point where all the three medians of the triangle intersect and the median is a line that joins the midpoint of a side and the opposite vertex of a triangle.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

