Find the compound interest on Rs. 20,000 for 2 years, compounded annually at 10% per annum.
A) 4200
B) 4300
C) 4400
D) 4500
Answer
661.8k+ views
Hint: First calculate the final amount needed to pay after two year then subtract this final amount to the given principal amount to calculate the compound interest in two years.
Complete step by step answer:
Given principal amount is
P=Rs 20000
Time to repay the amount is
T= 2 years
Rate of interest is
R=10% per annum
To find the amount of compound interest after 2 years
C.I. = ?
To calculate the compound interest first we will calculate the final amount that we need to pay after 2 year
We know that the formula to calculate the final amount
$$A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T}$$
On putting the given values
$$A = 20000 \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^2}$$
On simplification
$$A = 20000 \times \dfrac{{121}}{{100}}$$
Now we will calculate the compound interest
We know that
∴ $$C.I. = A - P$$
On putting the values of A and P
We get
$$ = Rs.24,200 - Rs.20,000$$
On subtracting
We get
$$ = Rs.4200.$$
Hence the compound interest that I need to pay after two year will be equal to Rs 4200.
Therefore the correct option is ‘A’
Additional information: When calculating compound interest, the number of compounding periods makes a significant difference. The basic rule is that the higher the number of compounding periods, the greater the amount of compound interest.
Note: The interest rate for the first year in compound interest is the same as that in case of simple interest, Other than the first year, the interest compounded annually is always greater than that in case of simple interest.
Complete step by step answer:
Given principal amount is
P=Rs 20000
Time to repay the amount is
T= 2 years
Rate of interest is
R=10% per annum
To find the amount of compound interest after 2 years
C.I. = ?
To calculate the compound interest first we will calculate the final amount that we need to pay after 2 year
We know that the formula to calculate the final amount
$$A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T}$$
On putting the given values
$$A = 20000 \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^2}$$
On simplification
$$A = 20000 \times \dfrac{{121}}{{100}}$$
Now we will calculate the compound interest
We know that
∴ $$C.I. = A - P$$
On putting the values of A and P
We get
$$ = Rs.24,200 - Rs.20,000$$
On subtracting
We get
$$ = Rs.4200.$$
Hence the compound interest that I need to pay after two year will be equal to Rs 4200.
Therefore the correct option is ‘A’
Additional information: When calculating compound interest, the number of compounding periods makes a significant difference. The basic rule is that the higher the number of compounding periods, the greater the amount of compound interest.
Note: The interest rate for the first year in compound interest is the same as that in case of simple interest, Other than the first year, the interest compounded annually is always greater than that in case of simple interest.
Recently Updated Pages
What are the two major island groups in India class 9 social science CBSE

What is Jhum cultivation class 9 biology CBSE

Write an Article on Save Earth Save Life

Silk is obtained from of the silk moth APupa BLarva class 9 chemistry CBSE

Write chemical formulas of the following compounds class 9 chemistry CBSE

The Indo Gangetic Plains of India are fertile due to class 9 social science CBSE

Trending doubts
Who was referred to as Amitraghata by the Greeks AChandragupta class 9 social science CBSE

On an outline map of India show its neighbouring c class 9 social science CBSE

Differentiate between parenchyma collenchyma and sclerenchyma class 9 biology CBSE

Distinguish between Khadar and Bhangar class 9 social science CBSE

The normal temperature of the human body on the Kelvin class 9 biology CBSE

Air is a A Homogenous mixture B Heterogeneous mixture class 9 chemistry CBSE

