Answer
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Hint: Let the combined equation of the asymptotes be \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+k=0\]. Then factorize the second degree terms and find the combined equation of asymptotes. Equate the two equations to find the constants. Then use the formula: Equation of hyperbola + equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes)
Complete step-by-step answer:
We are given the equation of the hyperbola: \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x-6=0\]
We know that the equation of a hyperbola and the combined equation of the asymptotes are the same except for the constant term.
Therefore the combined equation of the asymptotes is of the form:
\[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+k=0\], where k is a constant …(1)
Factorising the 2nd degree terms, we get the following:
\[{{y}^{2}}-xy-2{{x}^{2}}={{y}^{2}}-2xy+xy-2{{x}^{2}}=\left( y-2x \right)\left( y+x \right)\]
Therefore the asymptotes have equations: \[y-2x+l=0\] and \[y+x+m=0\],
Where l and m are constants.
Their combined equation will be: \[\left( y-2x+l \right)\left( y+x+m \right)=0\]
\[{{y}^{2}}-xy-2{{x}^{2}}+\left( m+l \right)y+\left( -2m+l \right)x+ml=0\] …(2)
Equations (1) and (2) represent the same pair of lines.
Now, we will compare the coefficients of x, y, and the constant terms, we will get the following:
\[m+l=-5\]
\[-2m+l=1\]
\[ml=k\]
From the first two conditions: \[m+l=-5\] and \[-2m+l=1\], we will solve for m and l.
Subtract the two equations, we get:
3m = -6
m = -2
Putting this in \[m+l=-5\], we get the following:
-2 + l = -5
l = -3
So, m = -2 and l = -3
And k = ml = 6
Therefore, the asymptotes are \[y-2x+-3=0\] and \[y+x+-2=0\], and their combined equation is \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+6=0\]
Now we know the fact that:
Equation of hyperbola + equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes)
So, Equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes) - equation of hyperbola
Equation of conjugate hyperbola = \[2~\times \left( {{y}^{2}}-xy-2{{x}^{2}}-5y+x+6 \right)-\left( {{y}^{2}}-xy-2{{x}^{2}}-5y+x-6 \right)\]
Hence, equation of conjugate hyperbola is \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+18=0\]
Note: In this question, it is important to know the various concepts of hyperbola like the equation of a hyperbola and the combined equation of the asymptotes are the same except for the constant term. You should also know the formula: Equation of hyperbola + equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes)
Complete step-by-step answer:
We are given the equation of the hyperbola: \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x-6=0\]
We know that the equation of a hyperbola and the combined equation of the asymptotes are the same except for the constant term.
Therefore the combined equation of the asymptotes is of the form:
\[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+k=0\], where k is a constant …(1)
Factorising the 2nd degree terms, we get the following:
\[{{y}^{2}}-xy-2{{x}^{2}}={{y}^{2}}-2xy+xy-2{{x}^{2}}=\left( y-2x \right)\left( y+x \right)\]
Therefore the asymptotes have equations: \[y-2x+l=0\] and \[y+x+m=0\],
Where l and m are constants.
Their combined equation will be: \[\left( y-2x+l \right)\left( y+x+m \right)=0\]
\[{{y}^{2}}-xy-2{{x}^{2}}+\left( m+l \right)y+\left( -2m+l \right)x+ml=0\] …(2)
Equations (1) and (2) represent the same pair of lines.
Now, we will compare the coefficients of x, y, and the constant terms, we will get the following:
\[m+l=-5\]
\[-2m+l=1\]
\[ml=k\]
From the first two conditions: \[m+l=-5\] and \[-2m+l=1\], we will solve for m and l.
Subtract the two equations, we get:
3m = -6
m = -2
Putting this in \[m+l=-5\], we get the following:
-2 + l = -5
l = -3
So, m = -2 and l = -3
And k = ml = 6
Therefore, the asymptotes are \[y-2x+-3=0\] and \[y+x+-2=0\], and their combined equation is \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+6=0\]
Now we know the fact that:
Equation of hyperbola + equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes)
So, Equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes) - equation of hyperbola
Equation of conjugate hyperbola = \[2~\times \left( {{y}^{2}}-xy-2{{x}^{2}}-5y+x+6 \right)-\left( {{y}^{2}}-xy-2{{x}^{2}}-5y+x-6 \right)\]
Hence, equation of conjugate hyperbola is \[{{y}^{2}}-xy-2{{x}^{2}}-5y+x+18=0\]
Note: In this question, it is important to know the various concepts of hyperbola like the equation of a hyperbola and the combined equation of the asymptotes are the same except for the constant term. You should also know the formula: Equation of hyperbola + equation of conjugate hyperbola = 2 \[\times \] (equation of asymptotes)
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