
Find the area of the shaded part in the figure: (Use π=3.14)
Answer
597k+ views
Hint: we will find the diagonal AC, since, AC represents the diameter of the circle. The radius of the circle is half of the diameter. From the radius, we found out we will find the area of the circle shown. Also, find the area of the rectangle from the given graph.
from the subtraction of the area of the rectangle from the area of the circle, we will get the area of the shaded portion.
Given: AD= 5cm, DC= 12cm
Formulas used:
Pythagoras theorem formula; \[\text{hypotenuse}{{\text{e}}^{2}}=\text{side}_{1}^{2}+\text{side}_{2}^{2}\]
Area of circle \[=\pi {{r}^{2}}\]
Area of a rectangle \[=\text{length}\times \text{breadth}\]
Complete Step by step solution:
\[\vartriangle \text{ACD}\] is a right angled triangle.
Using Pythagoras theorem formula;
\[\begin{gathered}
& A{{C}^{2}}=A{{D}^{2}}+D{{C}^{2}} \\
& A{{C}^{2}}={{5}^{2}}+{{12}^{2}} \\
& A{{C}^{2}}=25+144 \\
& A{{C}^{2}}=169 \\
& AC=\sqrt{169} \\
& AC=\pm \,13\text{ cm} \\
\end{gathered}\]
Since AC is a length it cannot be negative therefore AC= 13cm
Through AC which is the diameter of the circle, we can find the radius of the circle. from this circle, we will find the area of the circle.
Area of the shaded region \[=\] Area of the circle \[-\] area of the rectangle ABCD
Thus, by subtracting the area of the circle with the area of the inscribed rectangle we got the area of the shaded region.
from the subtraction of the area of the rectangle from the area of the circle, we will get the area of the shaded portion.
Given: AD= 5cm, DC= 12cm
Formulas used:
Pythagoras theorem formula; \[\text{hypotenuse}{{\text{e}}^{2}}=\text{side}_{1}^{2}+\text{side}_{2}^{2}\]
Area of circle \[=\pi {{r}^{2}}\]
Area of a rectangle \[=\text{length}\times \text{breadth}\]
Complete Step by step solution:
\[\vartriangle \text{ACD}\] is a right angled triangle.
Using Pythagoras theorem formula;
\[\begin{gathered}
& A{{C}^{2}}=A{{D}^{2}}+D{{C}^{2}} \\
& A{{C}^{2}}={{5}^{2}}+{{12}^{2}} \\
& A{{C}^{2}}=25+144 \\
& A{{C}^{2}}=169 \\
& AC=\sqrt{169} \\
& AC=\pm \,13\text{ cm} \\
\end{gathered}\]
Since AC is a length it cannot be negative therefore AC= 13cm
Through AC which is the diameter of the circle, we can find the radius of the circle. from this circle, we will find the area of the circle.
Area of the shaded region \[=\] Area of the circle \[-\] area of the rectangle ABCD
Thus, by subtracting the area of the circle with the area of the inscribed rectangle we got the area of the shaded region.
Recently Updated Pages
Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Trending doubts
A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

State and explain Ohms law class 10 physics CBSE

Distinguish between soap and detergent class 10 chemistry CBSE

a Why did Mendel choose pea plants for his experiments class 10 biology CBSE

What is a "free hit" awarded for in limited-overs cricket?

Draw the diagram of the sectional view of the human class 10 biology CBSE

