Question

Factorise the following expression: $7{a^2} + 14a$
${\text{A}}{\text{.}}$$7a\left( {a + 2} \right)$
${\text{B}}{\text{.}}$$7\left( {a - 2} \right)$
${\text{C}}{\text{.}}$$14\left( {7a + 2} \right)$
${\text{D}}{\text{.}}$$7a\left( {a - 2} \right)$

Answer 1

Hint: Take $7a$ common factors of the terms by the Factoring using the Common Factor Method.

Complete step-by-step answer:

According to the question, we have to factorise the $7{a^2} + 14a$
$ \Rightarrow $$7{a^2} + 14a$

Now, taking common factor $7a$ from both terms we get,
$ \Rightarrow 7a\left( {a + 2} \right)$

So, the option “A” is correct.

Note: Whenever you find such type of questions always use the concept of Factorization using the Common Factor Method which involves, factorise an algebraic expression, take out the highest common factor and place it in front of the brackets. Then the expression inside the brackets is obtained by dividing each term by the highest common factor.