Explain why ${O_2}$ molecule is paramagnetic in nature?
Answer
628.5k+ views
Hint: Try to recall the molecular orbital theory. By drawing the molecular orbital diagram of oxygen molecules, you can easily explain the paramagnetic nature of oxygen molecules. Also, it is known to you that for a molecule to be paramagnetic it must have at least an unpaired electron.
Complete step by step solution:
It is known to you that one of the greatest achievements of molecular orbital approach was that you could explain the paramagnetic nature of oxygen molecules which you could not explain by valence bond approach.
According to valence bond theory, oxygen molecule should like this:
The electronic configuration of an oxygen atom(Z=8) = $1{s^2}2{s^2}2{p^4}$. Valence bond theory considers that the atomic orbitals overlap to form bonds and due to this electron are paired in overlapping and it shows that oxygen is a diamagnetic species.
But experimentally it is found that oxygen molecules are paramagnetic in nature and this could be only explained by molecular orbital approach.
According to molecular orbital theory, the atomic orbitals of oxygen atoms overlap to form orbitals of the molecule which you can see in the below diagram.
The electronic configuration of Oxygen molecule (according to molecular orbital theory) is $(\sigma 1{s^2}\sigma *1{s^2})(\sigma 2{s^2}\sigma *2{s^2})(\sigma 2{p_z}^2)(\pi 2{p_x}^2 = \pi 2{p_y}^2)(\pi 2{p_x}^1 = \pi 2{p_y}^1)$.
where, $\sigma $ and $\pi $ indicates bonding molecular orbital
$\sigma *$ and $\pi *$ indicates antibonding molecular orbital.
From the above electronic configuration of the ${O_2}$ molecule, you can easily say that since, the last two electrons go into two separate, $\pi $ degenerate orbitals .
Therefore, you can easily say that ${O_2}$ has two unpaired electrons and is paramagnetic.
Note: It should be remembered that you can also find the bond order of oxygen molecules by using the electronic configuration of oxygen molecules.
Bond order is defined as “half the difference between the number of electrons in bonding orbitals and antibonding molecular orbitals”. It indicates number of bonds in the given compound
Complete step by step solution:
It is known to you that one of the greatest achievements of molecular orbital approach was that you could explain the paramagnetic nature of oxygen molecules which you could not explain by valence bond approach.
According to valence bond theory, oxygen molecule should like this:
The electronic configuration of an oxygen atom(Z=8) = $1{s^2}2{s^2}2{p^4}$. Valence bond theory considers that the atomic orbitals overlap to form bonds and due to this electron are paired in overlapping and it shows that oxygen is a diamagnetic species.
But experimentally it is found that oxygen molecules are paramagnetic in nature and this could be only explained by molecular orbital approach.
According to molecular orbital theory, the atomic orbitals of oxygen atoms overlap to form orbitals of the molecule which you can see in the below diagram.
The electronic configuration of Oxygen molecule (according to molecular orbital theory) is $(\sigma 1{s^2}\sigma *1{s^2})(\sigma 2{s^2}\sigma *2{s^2})(\sigma 2{p_z}^2)(\pi 2{p_x}^2 = \pi 2{p_y}^2)(\pi 2{p_x}^1 = \pi 2{p_y}^1)$.
where, $\sigma $ and $\pi $ indicates bonding molecular orbital
$\sigma *$ and $\pi *$ indicates antibonding molecular orbital.
From the above electronic configuration of the ${O_2}$ molecule, you can easily say that since, the last two electrons go into two separate, $\pi $ degenerate orbitals .
Therefore, you can easily say that ${O_2}$ has two unpaired electrons and is paramagnetic.
Note: It should be remembered that you can also find the bond order of oxygen molecules by using the electronic configuration of oxygen molecules.
Bond order is defined as “half the difference between the number of electrons in bonding orbitals and antibonding molecular orbitals”. It indicates number of bonds in the given compound
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

