
Evaluate
Answer
545.1k+ views
Hint: Use substitution method i.e. substitute for easy simplification.
Let,
As we know , so substitute this value.
Now, let
Differentiate above equation w.r.t.
As we know differentiation is
So, substitute this value in equation (1).
Now, integrate it, as we know , so apply this property.
, (where c is some arbitrary integration constant)
L.C.M of 5 and 7 is 35, and take as common
Now re-substitute the value of
So, this is the required value of the integration.
Note: In such types of questions always choose substitution which makes integration simple, in above integration we choose , so it makes integration simple, then we easily integrate using some basic property of integration which is stated above, then simplify we will get the required answer.
Let,
As we know
Now, let
Differentiate above equation w.r.t.
As we know
So, substitute this value in equation (1).
Now, integrate it, as we know
L.C.M of 5 and 7 is 35, and take
Now re-substitute the value of
So, this is the required value of the integration.
Note: In such types of questions always choose substitution which makes integration simple, in above integration we choose
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