How do you evaluate the expression for \[x = - 2\], \[y = 3\], \[z = - 4\,\,\] given \[7x - 2y - 8z?\]
Answer
617.1k+ views
Hint: This is a simple question of substitution. The values of the variables are given and an expression involving those variables is given. Just substitute the values given in the given expression and simplify.
Complete step by step answer:
The given expression is \[7x - 2y - 8z\]
If one closely observes, the expression involves some constants (their values can never be changed) and three variables. The values of these variables have to be found to make this into an expression containing only constants that could be further simplified. The variables involved in the equation are\[x\], \[y\] and \[z\] .
Now, in the question it is also given that \[x = - 2\], \[y = 3\] and\[z = - 4\,\,\]. This means the values of the variables are already given in the question, we don’t have to find these values.
Just by simply putting these values in the expression, we would be able to simplify the given expression.
So, substituting the values we get
\[
7\, \times \,\underbrace x_ \downarrow - 2 \times \underbrace y_ \downarrow - 8 \times \,\,\underbrace z_ \downarrow \\
7( - 2) - 2(3) - 8( - 4) \\
\]
Opening the brackets we get
\[ = - 14 - 6 + 32\]
By simplifications, we get
\[ = 12\]
Note:
A variable is a quantity whose value can be changed in the question. It is denoted by alphabets. Usually, they are used to indicate the quantities that are missing or are to be found. Constants are the digits whose value can never be changed in any question or situation.
\[\left( - \right) \times \left( - \right) = \left( + \right)\]
\[\left( - \right) \times \left( + \right) = \left( - \right)\]
\[\left( + \right) \times \left( - \right) = \left( - \right)\]
\[\left( + \right) \times \left( + \right) = \left( + \right)\]
Another property of integers used is while opening the brackets. Following rules are followed while opening the brackets.
If there is no operator in between the bracket and a digit, the operator assumed is always multiplication. It is necessary to keep in mind the signs of the while opening and closing the brackets.
In case of multiple operators in an expression, there is confusion about which operator should be solved first. In such a situation, follow BODMAS i.e. (Brackets followed by or followed by division then multiplication then addition and in the last subtraction).
Complete step by step answer:
The given expression is \[7x - 2y - 8z\]
If one closely observes, the expression involves some constants (their values can never be changed) and three variables. The values of these variables have to be found to make this into an expression containing only constants that could be further simplified. The variables involved in the equation are\[x\], \[y\] and \[z\] .
Now, in the question it is also given that \[x = - 2\], \[y = 3\] and\[z = - 4\,\,\]. This means the values of the variables are already given in the question, we don’t have to find these values.
Just by simply putting these values in the expression, we would be able to simplify the given expression.
So, substituting the values we get
\[
7\, \times \,\underbrace x_ \downarrow - 2 \times \underbrace y_ \downarrow - 8 \times \,\,\underbrace z_ \downarrow \\
7( - 2) - 2(3) - 8( - 4) \\
\]
Opening the brackets we get
\[ = - 14 - 6 + 32\]
By simplifications, we get
\[ = 12\]
Note:
A variable is a quantity whose value can be changed in the question. It is denoted by alphabets. Usually, they are used to indicate the quantities that are missing or are to be found. Constants are the digits whose value can never be changed in any question or situation.
\[\left( - \right) \times \left( - \right) = \left( + \right)\]
\[\left( - \right) \times \left( + \right) = \left( - \right)\]
\[\left( + \right) \times \left( - \right) = \left( - \right)\]
\[\left( + \right) \times \left( + \right) = \left( + \right)\]
Another property of integers used is while opening the brackets. Following rules are followed while opening the brackets.
If there is no operator in between the bracket and a digit, the operator assumed is always multiplication. It is necessary to keep in mind the signs of the while opening and closing the brackets.
In case of multiple operators in an expression, there is confusion about which operator should be solved first. In such a situation, follow BODMAS i.e. (Brackets followed by or followed by division then multiplication then addition and in the last subtraction).
Recently Updated Pages
Difference Between Prokaryotic Cells and Eukaryotic Cells

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

