
Elements of a matrix is represented by ${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$. Find the $2 \times 2$ matrix.
Answer
582.9k+ views
Hint: First express the $2 \times 2$ matrix in its standard form$\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$. Then calculate the elements of the matrix using the given formula ${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$.
Complete step-by-step answer:
In mathematics, a matrix (plural matrices) is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns. Example of a $2 \times 2$matrix is $\left| {\begin{array}{*{20}{c}}
2&5 \\
3&6
\end{array}} \right|$.
The size of a matrix is denoted by the number of rows and columns that a matrix contains.
The elements of a matrix is denoted by ${a_{ij}}$, it means that ${a_{ij}}$is the element in the $i$th row and $j$th column.
Here it is mentioned that ${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$
We have to find a $2 \times 2$ matrix.
So the matrix will be in the form $\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$
Now we have to calculate ${a_{11,}}{a_{12}},{a_{21}},{a_{22}}$ respectively.
${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$
So ${a_{11}} = \left| {\dfrac{{3 \times 1 - 1}}{2}} \right| = \dfrac{2}{2} = 1$
Similarly ${a_{12}} = \left| {\dfrac{{3 \times 1 - 2}}{2}} \right| = \dfrac{1}{2}$, ${a_{21}} = \left| {\dfrac{{3 \times 2 - 1}}{2}} \right| = \dfrac{5}{2}$ and ${a_{22}} = \left| {\dfrac{{3 \times 2 - 2}}{2}} \right| = \dfrac{4}{2} = 2$
So the required $2 \times 2$ matrix is $\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$
=$\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right| = \left| {\begin{array}{*{20}{c}}
1&{\dfrac{1}{2}} \\
{\dfrac{5}{2}}&2
\end{array}} \right|$
The required $2 \times 2$ matrix is $\left| {\begin{array}{*{20}{c}}
1&{\dfrac{1}{2}} \\
{\dfrac{5}{2}}&2
\end{array}} \right|$
Note: We should also remember various information of matrix regarding ${a_{ij}}$
For example: If a matrix is symmetric than we can say that ${a_{ij}} = {a_{ji}}$, whether if the matrix be skew symmetric then ${a_{ij}} = - {a_{ji}}$. For a null matrix ${a_{ij}} = 0$.
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$. Then calculate the elements of the matrix using the given formula ${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$.
Complete step-by-step answer:
In mathematics, a matrix (plural matrices) is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns. Example of a $2 \times 2$matrix is $\left| {\begin{array}{*{20}{c}}
2&5 \\
3&6
\end{array}} \right|$.
The size of a matrix is denoted by the number of rows and columns that a matrix contains.
The elements of a matrix is denoted by ${a_{ij}}$, it means that ${a_{ij}}$is the element in the $i$th row and $j$th column.
Here it is mentioned that ${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$
We have to find a $2 \times 2$ matrix.
So the matrix will be in the form $\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$
Now we have to calculate ${a_{11,}}{a_{12}},{a_{21}},{a_{22}}$ respectively.
${a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|$
So ${a_{11}} = \left| {\dfrac{{3 \times 1 - 1}}{2}} \right| = \dfrac{2}{2} = 1$
Similarly ${a_{12}} = \left| {\dfrac{{3 \times 1 - 2}}{2}} \right| = \dfrac{1}{2}$, ${a_{21}} = \left| {\dfrac{{3 \times 2 - 1}}{2}} \right| = \dfrac{5}{2}$ and ${a_{22}} = \left| {\dfrac{{3 \times 2 - 2}}{2}} \right| = \dfrac{4}{2} = 2$
So the required $2 \times 2$ matrix is $\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|$
=$\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right| = \left| {\begin{array}{*{20}{c}}
1&{\dfrac{1}{2}} \\
{\dfrac{5}{2}}&2
\end{array}} \right|$
The required $2 \times 2$ matrix is $\left| {\begin{array}{*{20}{c}}
1&{\dfrac{1}{2}} \\
{\dfrac{5}{2}}&2
\end{array}} \right|$
Note: We should also remember various information of matrix regarding ${a_{ij}}$
For example: If a matrix is symmetric than we can say that ${a_{ij}} = {a_{ji}}$, whether if the matrix be skew symmetric then ${a_{ij}} = - {a_{ji}}$. For a null matrix ${a_{ij}} = 0$.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

