
Electronic configuration of calcium is?
(a) $(Ar)4{{s}^ {3}} $
(b) $(Ne)3{{s}^ {2}} $
(c) $(Ar)4{{s}^ {2}} $
(d) $(Kr)4{{s}^ {2}} $
Answer
595.8k+ views
Hint: Here, the word electronic configuration tells us about the arrangement of electrons in the sub-shells. (it is just like the address of our house)
Complete step by step answer:
Electronic configuration is the distribution of electrons into orbitals of an atom.
• It can be represented in two ways-
I. ${{s}^{a}} {{p}^{b}} {{d}^{c}}$ .... notation
II. orbital diagram
In the first representation, the sub-shell is represented by the respective letter symbol and the number of electrons present in the subshell is depicted in the superscript, i.e., for example
$1{{s}^ {2}} $.
In orbital representation, each orbital of the sub-shell is represented by a square and the electron is represented by an upward arrow $(\uparrow) $for positive spin and by a downward arrow $(\downarrow) $a negative spin.
• For writing configuration, we should know the principal quantum numbers i.e. principle quantum number (n), azimuthal quantum number (l), magnetic quantum number (ml), spin quantum number (ms).
• Also, we have to keep some rules in our mind before writing electronic configuration. These rules are as follows-
4) AUFBAU PRINCIPLE – this rule states that ‘the orbitals are filled in order of their increasing energies’
5) PAULI EXCLUSION PRINCIPLE – it states that ‘No two electrons in an atom can have the same set of four quantum numbers’
6) HUND’S RULE – it states that in filling a particular subshell electron are first singly filled before doubly filled.
• Now, using above rules we will write electronic configuration of calcium (atomic no. is twenty)
Ca = $1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^ {2}} $
Since we know that Argon has configuration as $1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}$ , so by replacing it in calcium’s configuration. We get,
Ca = $(Ar)4{{s}^ {2}} $
Therefore, option (c) is correct.
Note: Without knowledge of quantum numbers and some rules you will not be able to write electronic configuration, so it must be advisable that we have to ponder these rules.
Complete step by step answer:
Electronic configuration is the distribution of electrons into orbitals of an atom.
• It can be represented in two ways-
I. ${{s}^{a}} {{p}^{b}} {{d}^{c}}$ .... notation
II. orbital diagram
In the first representation, the sub-shell is represented by the respective letter symbol and the number of electrons present in the subshell is depicted in the superscript, i.e., for example
$1{{s}^ {2}} $.
In orbital representation, each orbital of the sub-shell is represented by a square and the electron is represented by an upward arrow $(\uparrow) $for positive spin and by a downward arrow $(\downarrow) $a negative spin.
• For writing configuration, we should know the principal quantum numbers i.e. principle quantum number (n), azimuthal quantum number (l), magnetic quantum number (ml), spin quantum number (ms).
• Also, we have to keep some rules in our mind before writing electronic configuration. These rules are as follows-
4) AUFBAU PRINCIPLE – this rule states that ‘the orbitals are filled in order of their increasing energies’
5) PAULI EXCLUSION PRINCIPLE – it states that ‘No two electrons in an atom can have the same set of four quantum numbers’
6) HUND’S RULE – it states that in filling a particular subshell electron are first singly filled before doubly filled.
• Now, using above rules we will write electronic configuration of calcium (atomic no. is twenty)
Ca = $1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^ {2}} $
Since we know that Argon has configuration as $1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}$ , so by replacing it in calcium’s configuration. We get,
Ca = $(Ar)4{{s}^ {2}} $
Therefore, option (c) is correct.
Note: Without knowledge of quantum numbers and some rules you will not be able to write electronic configuration, so it must be advisable that we have to ponder these rules.
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