
Electron density in the \[{\text{yz}}\] plane of \[{\text{3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}\] orbital is
A) Zero
B) \[0.50\]
C) \[0.75\]
D) \[0.90\]
Answer
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Hint: As we know that in chemistry, an atom is the smallest particle. Atoms are the building blocks of the elements. The atom is made of electrons, neutrons and protons. The electrons revolve around the nucleus. The nucleus is made up of protons and neutrons in the atom. The electrons are filled in specific orbitals in the energy level.
Complete answer:
We have to remember that the principal quantum number depends on the energy level or shell of the atom. The azimuthal quantum number depends on the shape of the orbital of electrons in the shell. The magnetic quantum number depends on the orientation of the electron in the orbital. The spin quantum number depends on the spin of the electron in the orbit.
There are four shapes of orbits seen in the atom. There are s, p, d and f. Each shape of orbit has a specific orientation.
The d shape orbitals have five orientations. There are \[{\text{3}}{{\text{d}}_{{\text{xy}}}}{\text{,3}}{{\text{d}}_{{\text{yz}}}}{\text{,3}}{{\text{d}}_{{\text{zx}}}}{\text{,3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}{\text{and3}}{{\text{d}}_{{z^{\text{2}}}}}\].
In \[{\text{3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}\] orbital electron density in the \[{\text{yz}}\] plane is zero. Because the electrons are present in the lobe of the x and y axis of the orbitals.
According to the above discussion we conclude is
Electron density in the \[{\text{yz}}\]plane of \[{\text{3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}\]orbital is zero.
Hence, option A is correct.
Note:
As we know that quantum numbers play a major role in chemistry. There are four types of quantum number. There are principal quantum number, azimuthal quantum number, magnetic quantum number and spin quantum number. Each quantum number has a specific symbol. The symbol of principal quantum number is n. The symbol of azimuthal quantum number is l. The symbol of magnetic quantum number is m. The symbol of principal quantum number is s. Another name of azimuthal quantum number is subsidiary quantum number.
Complete answer:
We have to remember that the principal quantum number depends on the energy level or shell of the atom. The azimuthal quantum number depends on the shape of the orbital of electrons in the shell. The magnetic quantum number depends on the orientation of the electron in the orbital. The spin quantum number depends on the spin of the electron in the orbit.
There are four shapes of orbits seen in the atom. There are s, p, d and f. Each shape of orbit has a specific orientation.
The d shape orbitals have five orientations. There are \[{\text{3}}{{\text{d}}_{{\text{xy}}}}{\text{,3}}{{\text{d}}_{{\text{yz}}}}{\text{,3}}{{\text{d}}_{{\text{zx}}}}{\text{,3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}{\text{and3}}{{\text{d}}_{{z^{\text{2}}}}}\].
In \[{\text{3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}\] orbital electron density in the \[{\text{yz}}\] plane is zero. Because the electrons are present in the lobe of the x and y axis of the orbitals.
According to the above discussion we conclude is
Electron density in the \[{\text{yz}}\]plane of \[{\text{3}}{{\text{d}}_{{{\text{x}}^{\text{2}}}{\text{ - }}{{\text{y}}^{\text{2}}}}}\]orbital is zero.
Hence, option A is correct.
Note:
As we know that quantum numbers play a major role in chemistry. There are four types of quantum number. There are principal quantum number, azimuthal quantum number, magnetic quantum number and spin quantum number. Each quantum number has a specific symbol. The symbol of principal quantum number is n. The symbol of azimuthal quantum number is l. The symbol of magnetic quantum number is m. The symbol of principal quantum number is s. Another name of azimuthal quantum number is subsidiary quantum number.
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