Question

What is the effect of pressure on the equilibrium of the reaction of nitrogen and oxygen to give nitric oxide?
A.Pressure increases
B.Pressure decreases
C.Remains same
D.Pressure changes with change in equilibrium

Answer 1

Hint: Nitrogen and oxygen react with each other to form nitric oxide. When the number of moles of reactants and the number of moles of products are the same. Then, there is no effect of pressure on equilibrium of the reaction. In the above reaction there is an equal number of moles of reactants and products.

Complete answer: Atoms involved in the bond formation to form molecules or compounds. Nitrogen and oxygen are atoms. These two atoms share their electrons and form a compound called nitric oxide. Nitric oxide is an oxide with a chemical formula of \[NO\].
The chemical reaction involved between the nitrogen and oxygen to form nitric oxide will be as follows:
\[{N_2} + {O_2} \to 2NO\]
The total number of moles of reactants are two. The total number of moles of products in the above reaction are two. As the total number of moles and reactants are equal, there is no effect of pressure on the equilibrium of the reaction of nitrogen and oxygen to give nitric oxide.
Thus, the pressure remains the same.
Hence option C is the correct answer.

Note:
The moles of nitrogen in the above reaction are one, the moles of oxygen in the above reaction are one. While calculating the moles of reactants all the reactants must be considered. If there is a difference in moles of reactants and products the equilibrium shifts towards the lesser moles of reaction.