During the formation of water molecules, the hydrogen atoms. A.Accepts electron from the oxygen atom B.Donate electrons from the oxygen atom C.Shares electron with the oxygen atom D.None of the above
Hint: Hydrogen is the atom with atomic number \[1\] , so it’s just a proton and has only the \[s\] orbital in it so it does not need to complete its octet. It is satisfied or made stable by the duplex. Whereas on the other hand Oxygen’s atomic number is \[8\]. So it has both \[s\] and \[p\] orbital.
Complete answer: So, now we know that for the water molecule to be stable the hydrogen atom needs to complete its duplex and the oxygen atom needs to complete its octet. And the above condition is only possible when there is sharing of electrons. So, the hydrogen atom shares electrons with the hydrogen atom. As there are two hydrogen atoms present in a water, each having one electron which they share with the oxygen atom having \[6\] valence electrons. In this way hydrogen and oxygen complete each other by sharing electrons and forming a stable water molecule. Thus, on the basis of our discussion, the correct answer is option C.
Note: Water molecules are made by the interaction of hydrogen bonding. Hydrogen bonding is the formation of bonds between hydrogen atoms with a highly electronegative element like nitrogen, oxygen etc. Hydrogen bonding is one of the strongest bonds. However, there are two types of hydrogen bonding – Intermolecular hydrogen bonding and Intramolecular hydrogen bonding.