Questions & Answers
Question
Answers
Related Questions
During electrolysis of fused calcium hydride, the hydrogen is produced at:
A. cathode
B. anode
C. hydrogen is not liberated at all
D. ${{\text{H}}_{2}}$ produced reacts with oxygen to form water
Answer
![Verified]()
Verified
Verified
Hint: Initially the ionic compound $\left( \text{Ca}{{\text{H}}_{2}} \right)$ will ionise as the solution is aqueous. Then, see the charges that made them move towards their opposite sites respectively. Then, by reduction or oxidation form the products that will be obtained on the electrodes.
Complete answer:
Let us see the solution of this question step by step:
Step (1)- In aqueous solution, the ionic compound which is calcium hydride or $\text{Ca}{{\text{H}}_{2}}$ will ionise. The ionization of this ionic compound will lead to the formation of $\text{C}{{\text{a}}^{+2}}$ (calcium ions) and $\text{2}{{\text{H}}^{-}}$(hydride ions) ions. The reaction is $\text{Ca}{{\text{H}}_{2}}\to \text{C}{{\text{a}}^{+2}}+\text{2}{{\text{H}}^{-}}$.
Step (2)- As calcium ions have positive charge, it will move towards the negative electrode (cathode for reduction). Whereas, hydride ions formed will move towards the positive electrode as it is negatively charged. The positive electrode is anode. Anode will cause the hydride ions to oxidise.
Step (3)- The reduction and oxidation will occur at cathode and anode respectively, as,
$\text{C}{{\text{a}}^{+2}}+2{{\text{e}}^{-}}\to \text{Ca}$ (this is reduction of calcium ions to form element calcium after gaining two electrons). This is reduction because the oxidation state of calcium changes from +2 to 0, which is decreasing.
Similarly, the oxidation process is $\text{2}{{\text{H}}^{-}}\to {{\text{H}}_{2}}+2{{\text{e}}^{-}}$ (After losing two electrons, hydrogen gas is produced at anode). The oxidation state is increasing from -2 to 0, thus, it is oxidation.
The correct answer to this question is the electrolysis products of fused calcium hydride are hydrogen gas and calcium and hydrogen gas is produced at anode,
So, the correct answer is “Option B”.
Additional Information:
Uses of calcium hydride:
(1)- It is highly used for the production of hydrogen gas.
(2)- It is a reducing agent, which produces metal from the metal oxides of Ti, V and Nb.
(3)- It reacts vigorously with water to produce hydrogen gas. Thus, it is used as a drying agent or mild desiccant also. It is also used to dry alcohol.
Note: The answer to this question can be achieved directly, as gases are generally produced or obtained at anode. Because their respective ions are negatively charged, they undergo oxidation which occurs at anode.
Complete answer:
Let us see the solution of this question step by step:
Step (1)- In aqueous solution, the ionic compound which is calcium hydride or $\text{Ca}{{\text{H}}_{2}}$ will ionise. The ionization of this ionic compound will lead to the formation of $\text{C}{{\text{a}}^{+2}}$ (calcium ions) and $\text{2}{{\text{H}}^{-}}$(hydride ions) ions. The reaction is $\text{Ca}{{\text{H}}_{2}}\to \text{C}{{\text{a}}^{+2}}+\text{2}{{\text{H}}^{-}}$.
Step (2)- As calcium ions have positive charge, it will move towards the negative electrode (cathode for reduction). Whereas, hydride ions formed will move towards the positive electrode as it is negatively charged. The positive electrode is anode. Anode will cause the hydride ions to oxidise.
Step (3)- The reduction and oxidation will occur at cathode and anode respectively, as,
$\text{C}{{\text{a}}^{+2}}+2{{\text{e}}^{-}}\to \text{Ca}$ (this is reduction of calcium ions to form element calcium after gaining two electrons). This is reduction because the oxidation state of calcium changes from +2 to 0, which is decreasing.
Similarly, the oxidation process is $\text{2}{{\text{H}}^{-}}\to {{\text{H}}_{2}}+2{{\text{e}}^{-}}$ (After losing two electrons, hydrogen gas is produced at anode). The oxidation state is increasing from -2 to 0, thus, it is oxidation.
The correct answer to this question is the electrolysis products of fused calcium hydride are hydrogen gas and calcium and hydrogen gas is produced at anode,
So, the correct answer is “Option B”.
Additional Information:
Uses of calcium hydride:
(1)- It is highly used for the production of hydrogen gas.
(2)- It is a reducing agent, which produces metal from the metal oxides of Ti, V and Nb.
(3)- It reacts vigorously with water to produce hydrogen gas. Thus, it is used as a drying agent or mild desiccant also. It is also used to dry alcohol.
Note: The answer to this question can be achieved directly, as gases are generally produced or obtained at anode. Because their respective ions are negatively charged, they undergo oxidation which occurs at anode.
×
Sorry!, This page is not available for now to bookmark.
Like this
Liked
-
LIVECourses
-
Crash Courses 2021
-
Vedantu Pro
-
Vedantu Assist
-
Class 12
-
-
JEE
-
JEE Main & Advanced 2021
-
JEE Main & Advanced 2022
-
-
NEET
-
NEET 2021
-
NEET 2022
-
-
NDA
-
CBSE
-
Commerce
-
Class 11
-
Class 12
-
-
ICSE
-
Maharashtra Board
-
Class 9
-
Class 10
-
-
Micro Courses
-
-
FREEMaster Classes
-
PREMIUM1-on-1 Classes
-
Study Material
-
NCERT Solutions
-
Previous Year Papers
-
Mock Tests
-
Sample Papers
-
Reference Book Solutions
-
ICSE Solutions
-
School Syllabus
-
Revision Notes
-
Important Questions
-
Math Formula Sheets
-
-
More
Book your FREE Online counselling session
Share your contact information
Your FREE Online counselling session has been booked!
Vedantu academic counsellor will be calling you shortly for your Online Counselling session.
DONE
Please try again later
OK
NCERT Book Solutions
Reference Book Solutions
Toll Free:
1800-120-456-456
Mobile:
+91 988-660-2456
Toll Free:
1800-120-456-456
Mobile:
+91 988-660-2456
(Mon-Sun: 9am - 11pm IST)
Questions?
Chat with us
