Question

Draw the graph of straight line $y=x-3$.

Answer 1

Hint: We will first start by using a fact that a line of form $y=mx+c$ is a straight line. Then we will use the basic plotting technique of finding x and y values which satisfies the curve and use the same for plotting on the Cartesian plane.

Complete step-by-step answer:
Now, we have to draw the graph of the straight line $y=x-3$.
Now, we know that the slope intercept form equation of a straight line is $y=mx+c$ and its graph is,

Now, we have to draw the graph of $y=x-3$ which is similar to $y=mx+c$.
Now, we have for different values of x the different values which satisfy the curve $y=x-3$ as $\left( 0,-3 \right),\left( 3,0 \right)$.
Now, we plot the points on the Cartesian plane and go to them.
 

So, we have the graph of $y=x-3$ as above.

Note:It is important to note that we have used the fact that the slope – intercept form of line is $y=mx+c$. Also, we have plot two points which satisfy $y=x-3$ and join them to draw the graph of $y=x-3$ as we know that a unique passes through two points.