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# How does a mixture of $C{{H}_{3}}COOH$ and $C{{H}_{3}}COONa$act as a buffer when a small amount of $NaOH$ is added?

Last updated date: 24th Mar 2023
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A mixture of a weak acid and its salt with a strong base serves as an acidic buffer: $C{{H}_{3}}COO{{H}_{\left( aq \right)}}+{{H}_{2}}{{O}_{\left( l \right)}}\to CH3COO_{\left( aq \right)}^{-}+{{H}_{3}}O_{\left( aq \right)}^{+}.$ $C{{H}_{3}}COOH$ is a weak acid, while is a weak base. So, if $~NaOH$ is added to the system the following reaction occurs: $C{{H}_{3}}COO{{H}_{\left( aq \right)}}+NaO{{H}_{\left( aq \right)}}\to CH3COO_{\left( aq \right)}^{-}+{{H}_{2}}{{O}_{\left( l \right)}}+Na_{\left( aq \right)}^{+}.$
The reaction shows that some acetic acids react with the $OH$ from the base and converts it to water. Therefore, the pH will not change as drastically as it would have without the buffer. Sodium acetate ionizes completely providing the acetate ion, $C{{H}_{3}}CO{{O}^{}}.$