Question

How do you divide $\dfrac{5{{x}^{4}}+2{{x}^{3}}-9x+14}{{{x}^{2}}-3x+4}$?

Answer 1

Hint: We will solve the given expression by using the long division method. For this first we will write the all terms in decreasing power of the variable order including the missing terms. Then we start dividing the terms by following the step by step procedure.

Complete step-by-step answer:
We have been given an expression $\dfrac{5{{x}^{4}}+2{{x}^{3}}-9x+14}{{{x}^{2}}-3x+4}$.
We have to divide the expression.
We will solve the given expression by using the long division method.
For long division methods first we will arrange the terms in decreasing power of the variable order including the missing terms. Then we get the dividend as \[5{{x}^{4}}+2{{x}^{3}}+0.{{x}^{2}}-9x+14\]. In algebraic long division methods we need to follow the same steps as we follow in the arithmetic division.
Now, let us start dividing the terms by long division method. Then we will get
\[{{x}^{2}}-3x+4\overset{5{{x}^{2}}+17x+31}{\overline{\left){\begin{align}
  & 5{{x}^{4}}+2{{x}^{3}}+0.{{x}^{2}}-9x+14 \\
 & \underline{5{{x}^{4}}-15{{x}^{3}}+20{{x}^{2}}} \\
 & 0+17{{x}^{3}}-20{{x}^{2}}-9x \\
 & \underline{17{{x}^{3}}-51{{x}^{2}}+68x} \\
 & 0+31{{x}^{2}}-77x+12 \\
 & \underline{31{{x}^{2}}-93x+124} \\
 & 0+16x-112 \\
\end{align}}\right.}}\]
So on dividing the given expression $\dfrac{5{{x}^{4}}+2{{x}^{3}}-9x+14}{{{x}^{2}}-3x+4}$ by using long division method we get the quotient as \[5{{x}^{2}}+17x+31\] and remainder as \[16x-112\].

Note: We can also check our answer by using the formula that $\text{Dividend=quotient}\times \text{divisor+remainder}\text{.}$. So by substituting the values we can verify the answer. The point to be noted is that if the terms are not in decreasing power of variable then we need to arrange the terms in decreasing power of the variable order including the missing terms.